Question

Какая масса гидроесида натрия потребуеться на нейтрализацию 9,8г серной кислоты? 1)800г; 2)400г;3)8г;4)4г

Answer 1

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Answer 2

Calculation of Sodium Hydrosulfide Mass Required for Neutralization

To calculate the mass of sodium hydrosulfide required to neutralize 9.8g of sulfuric acid, we can use the following chemical equation:

NaSH + H2SO4 → Na2SO4 + H2S

From the equation, we can see that 1 mole of sodium hydrosulfide (NaSH) reacts with 1 mole of sulfuric acid (H2SO4).

The molar mass of sulfuric acid (H2SO4) is 98.08 g/mol, and the molar mass of sodium hydrosulfide (NaSH) is 56.06 g/mol.

Using the molar ratio, we can calculate the mass of sodium hydrosulfide required.

Calculation

The molar ratio of NaSH to H2SO4 is 1:1.

Given: - Mass of sulfuric acid (H2SO4) = 9.8g

Using the molar masses: - Molar mass of H2SO4 = 98.08 g/mol - Molar mass of NaSH = 56.06 g/mol

We can calculate the number of moles of H2SO4: moles of H2SO4 = mass / molar mass = 9.8g / 98.08 g/mol = 0.1 moles

Since the molar ratio of NaSH to H2SO4 is 1:1, the number of moles of NaSH required is also 0.1 moles.

Finally, we can calculate the mass of NaSH required: mass = moles * molar mass = 0.1 moles * 56.06 g/mol = 5.606g

Answer

The mass of sodium hydrosulfide required to neutralize 9.8g of sulfuric acid is 5.606g. Therefore, the correct option is 4) 4g.