Question

Расставьте коэффициенты методом электронного баланса: B+NaOH+O2=NaBO2+H2O

Answer 1

4B +4NaOH + 3O2= 4NaBO2+ 2H2O
    B0 - 3e =B+3 | 4             восстановитель
    O2 + 4e = 2O-2 | 3         окислитель

Answer 2

Balancing the Chemical Equation B + NaOH + O2 = NaBO2 + H2O

To balance the chemical equation B + NaOH + O2 = NaBO2 + H2O using the method of electronic balance, we need to ensure that the same number of each type of atom is present on both sides of the equation.

The unbalanced equation is: B + NaOH + O2 = NaBO2 + H2O

Step 1: Count the Atoms on Each Side of the Equation

- B: 1 on the left - Na: 1 on the left, 1 in NaBO2 - O: 2 in NaOH, 2 in O2, 1 in NaBO2, 1 in H2O - H: 1 in NaOH, 2 in H2O

Step 2: Balance the Equation

1. Balance the atoms that appear only once on each side of the equation first. In this case, it's B and Na. 2. Then, balance the oxygen atoms by adding coefficients to the compounds containing oxygen. 3. Finally, balance the hydrogen atoms.

Balanced Equation

The balanced equation for B + NaOH + O2 = NaBO2 + H2O is: 2B + 2NaOH + 3O2 = 2NaBO2 + 3H2O

This equation ensures that the same number of each type of atom is present on both sides of the equation, satisfying the law of conservation of mass.