Question

Какую массу воды нужно выпарить из 200г 5% раствора хлорида натрия. Чтобы получить 11% раствор

Answer 1

M(NaCl) = m1()*w1 = 200 г*0,05 = 10 г
Эта  масса должна составить 11% в новом растворе. Масса второго раствора: m2() = m(NaCl)/w2 = 10 г/0,11 = 90,9 г
выпарить нужно воды: 200 - 90,9 = 109,1 г

Answer 2

Calculating the Mass of Water Needed to Evaporate

To calculate the mass of water that needs to be evaporated from 200g of a 5% solution of sodium chloride to obtain an 11% solution, we can use the formula:

Initial mass of solute = Final mass of solute

Let's calculate the mass of water that needs to be evaporated.

The initial mass of sodium chloride in the 5% solution can be calculated using the formula: Initial mass of solute = (5/100) * 200g

The final mass of sodium chloride in the 11% solution can be calculated using the formula: Final mass of solute = (11/100) * (200g - x), where x is the mass of water evaporated.

Equating the initial and final masses of solute, we get: (5/100) * 200g = (11/100) * (200g - x)

Solving for x gives us the mass of water that needs to be evaporated.

Let's calculate the value of x.

Calculation: Initial mass of solute = (5/100) * 200g = 10gFinal mass of solute = (11/100) * (200g - x) = 22g - 0.11x

Equating the initial and final masses of solute: 10g = 22g - 0.11x 0.11x = 22g - 10g 0.11x = 12g x = 12g / 0.11 x ≈ 109g

Answer: The mass of water that needs to be evaporated from 200g of a 5% solution of sodium chloride to obtain an 11% solution is approximately 109 grams.