Question

Какая масса органического вещества получится при взаимодействии 50г уксусной кислоты и 40г этиорвого спирта

Answer 1

Решение данной задачи в фото ниже. успеха!

Answer 2

ОТВЕТ ДАН НА БУМАГЕ СМОТРИТЕ НИЖЕ

Answer 3

Calculation of the Mass of Organic Compound

To calculate the mass of the organic compound produced by the reaction between 50g of acetic acid and 40g of ethyl alcohol, we can use the concept of chemical reactions and stoichiometry.

The balanced chemical equation for the reaction between acetic acid (CH3COOH) and ethyl alcohol (C2H5OH) to form ethyl acetate (CH3COOC2H5) and water (H2O) is as follows:

CH3COOH + C2H5OH → CH3COOC2H5 + H2O

Stoichiometry Calculation

To find the mass of the organic compound produced, we can use the concept of stoichiometry, which involves the quantitative relationships between reactants and products in a chemical reaction.

The molar mass of acetic acid (CH3COOH) is approximately 60.05 g/mol, and the molar mass of ethyl alcohol (C2H5OH) is approximately 46.07 g/mol.

Using the balanced chemical equation, we can calculate the theoretical yield of the organic compound produced by the reaction.

Calculation Steps

1. Calculate the number of moles of acetic acid and ethyl alcohol: - Moles of acetic acid = Mass of acetic acid / Molar mass of acetic acid - Moles of ethyl alcohol = Mass of ethyl alcohol / Molar mass of ethyl alcohol

2. Determine the limiting reactant: - Compare the moles of acetic acid and ethyl alcohol to identify the limiting reactant.

3. Calculate the theoretical yield of the organic compound: - Use the stoichiometry of the balanced chemical equation to calculate the theoretical yield of the organic compound produced.

Result

The mass of the organic compound produced can be calculated using the above steps. Let's proceed with the calculations.

Calculation

First, let's calculate the moles of acetic acid and ethyl alcohol:

Moles of acetic acid = 50g / 60.05 g/mol = 0.832 moles Moles of ethyl alcohol = 40g / 46.07 g/mol = 0.869 moles

Since acetic acid has fewer moles than ethyl alcohol, it is the limiting reactant.

Now, we can use the stoichiometry of the balanced chemical equation to calculate the theoretical yield of the organic compound produced.

The molar ratio of acetic acid to ethyl acetate is 1:1. Therefore, the moles of acetic acid will be equal to the moles of ethyl acetate produced.

The molar mass of ethyl acetate (CH3COOC2H5) is approximately 88.11 g/mol.

Theoretical yield of ethyl acetate = Moles of acetic acid × Molar mass of ethyl acetate Theoretical yield of ethyl acetate = 0.832 moles × 88.11 g/mol = 73.36g

The mass of the organic compound (ethyl acetate) produced by the reaction is approximately 73.36 grams.

This calculation assumes ideal conditions and complete conversion of reactants to products.

I hope this helps! If you have further questions, feel free to ask.