
К 106г раствора кароната натрия добавили избыток соляной кислоты,Найти какое кол-во соляной кислоты
прореагировало.Сколько грамм углекислого газа получено и сколько молекул воды образовалось.

Ответы на вопрос




n(NA2CO3)=106/106г/моль=1 моль
n(hcl)=2 моли N(HCL)=6,02Х10В 23 СТЕПЕНИ Х2=12,04
n(co2)=1 моль
m(co2)=44г/мольх1=44г



Calculation of the Amount of Hydrochloric Acid Reacted
To find the amount of hydrochloric acid that reacted with the excess sodium carbonate solution, we need to use the balanced chemical equation for the reaction between sodium carbonate (Na2CO3) and hydrochloric acid (HCl):
Na2CO3 + 2HCl → 2NaCl + H2O + CO2
From the equation, we can see that 1 mole of sodium carbonate reacts with 2 moles of hydrochloric acid. Therefore, the molar ratio between sodium carbonate and hydrochloric acid is 1:2.
Given that we have a 106 g solution of sodium carbonate, we need to determine the molar concentration of the sodium carbonate solution. Unfortunately, the search results provided do not contain the necessary information to calculate the molar concentration of the sodium carbonate solution. Therefore, we cannot proceed with the calculation of the amount of hydrochloric acid reacted.
Calculation of the Amount of Carbon Dioxide Produced
Similarly, to calculate the amount of carbon dioxide produced, we need to know the molar concentration of the sodium carbonate solution. Without this information, we cannot determine the amount of carbon dioxide produced.
Calculation of the Number of Water Molecules Formed
To calculate the number of water molecules formed, we need to know the amount of hydrochloric acid reacted, which we were unable to determine due to the lack of information about the molar concentration of the sodium carbonate solution.
Therefore, without the necessary information, we cannot provide a detailed calculation of the amount of hydrochloric acid reacted, the grams of carbon dioxide produced, or the number of water molecules formed in the given scenario.
If you have any additional information or specific values, please provide them so that we can assist you further.


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