Question

HELP!!! СРОЧНО НУЖНО!!! ПОМОГИТЕ ПОЖАЛУЙСТА!!!! Закончить уравнение, записать в ионной форме, окислительно-восстановительную реакцию б)pb(no3)2+naoh(изб)-> в) nh4cn+h2o<-> г) na2sio3+h2<->

Answer 1

реакций ОВР здесь нет

Answer 2

Balancing the Equation:

To balance the given equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's balance each part of the equation step by step.

a) Pb(NO3)2 + NaOH ->

First, let's balance the elements other than hydrogen and oxygen. We have one lead (Pb) atom on the left side and one on the right side, so they are already balanced.

Next, let's balance the nitrogen (N) atoms. We have two nitrate (NO3) groups on the left side, which contain a total of two nitrogen atoms. Therefore, we need two ammonia (NH3) molecules on the right side to balance the nitrogen atoms.

Now, let's balance the oxygen (O) atoms. We have six oxygen atoms on the left side (two from Pb(NO3)2 and four from NaOH). To balance this, we need three water (H2O) molecules on the right side, as each water molecule contains two hydrogen atoms and one oxygen atom.

The balanced equation for part a) is:

Pb(NO3)2 + 2NaOH -> Pb(OH)2 + 2NH3 + H2O [[1]]

b) NH4CN + H2O <->

In this part of the equation, we have ammonia cyanide (NH4CN) reacting with water (H2O). This is a reversible reaction, indicated by the double-headed arrow.

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides.

First, let's balance the nitrogen (N) atoms. We have one nitrogen atom on the left side from NH4CN. Therefore, we need one nitrogen atom on the right side as well.

Next, let's balance the hydrogen (H) atoms. We have four hydrogen atoms on the left side (from NH4CN) and two hydrogen atoms on the right side (from H2O). To balance this, we need to add two more water molecules on the right side, as each water molecule contains two hydrogen atoms.

The balanced equation for part b) is:

NH4CN + 2H2O <-> NH3 + HCN + H3O+ [[2]]

c) Na2SiO3 + H2 <->

In this part of the equation, we have sodium silicate (Na2SiO3) reacting with hydrogen gas (H2).

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides.

First, let's balance the sodium (Na) atoms. We have two sodium atoms on the left side from Na2SiO3. Therefore, we need two sodium atoms on the right side as well.

Next, let's balance the silicon (Si) atoms. We have one silicon atom on the left side from Na2SiO3. Therefore, we need one silicon atom on the right side as well.

Finally, let's balance the hydrogen (H) atoms. We have two hydrogen atoms on the left side (from H2) and six hydrogen atoms on the right side (from Na2SiO3). To balance this, we need to add three more hydrogen molecules on the left side.

The balanced equation for part c) is:

3H2 + Na2SiO3 <-> 2NaH + SiO2 [[3]]

Please note that the above-balanced equations are based on the given reactants and products. However, it is always recommended to double-check the balanced equations using appropriate chemical principles and calculations.

I hope this helps! Let me know if you have any further questions.