Question

Составьте окислительно-восстановительные уравнения, укажите окислитель и восстановитель.1)C + H_{2}SO_{4} ---> CO_{2} + SO_{2} +H_{2}O2)S + HNO_{3} ---> H_{2}SO_{4} + NO_{2} + H_{2}O

Answer 1

C + 2 H2SO4 =CO2? + 2 SO2? + 2 H2O.

Вос-ль С^0 -4e = C^+4

Оки-ль S^+6 +2e = S^+4

S + 2 HNO3 = H2SO4 + 2 NO

Вос-ль S^0 -6e = S^+6

Оки-ль N^+5 +3e = N^+2

Answer 2

Okislitelno-Vosstanovitelnye Urovneniya (Окислительно-восстановительные уравнения)

1) C + H2SO4 → CO2 + SO2 + H2O

To balance this equation, we need to assign oxidation numbers to each element and identify the changes in oxidation states. In this reaction, carbon (C) is oxidized from an oxidation state of 0 to +4, while sulfur (S) is reduced from an oxidation state of +6 to +4.

The balanced equation is:

C + 2H2SO4 → CO2 + 2SO2 + 2H2O

In this reaction, carbon (C) is the reducing agent (it undergoes oxidation) and sulfur (S) is the oxidizing agent (it undergoes reduction).

2) S + HNO3 → H2SO4 + NO2 + H2O

To balance this equation, we need to assign oxidation numbers to each element and identify the changes in oxidation states. In this reaction, sulfur (S) is oxidized from an oxidation state of 0 to +6, while nitrogen (N) is reduced from an oxidation state of +5 to +4.

The balanced equation is:

2S + 8HNO3 → 2H2SO4 + 4NO2 + 4H2O

In this reaction, sulfur (S) is the reducing agent (it undergoes oxidation) and nitrogen (N) is the oxidizing agent (it undergoes reduction).

Please note that the balanced equations provided above are based on the given chemical reactions. However, it is always recommended to double-check the balanced equations using appropriate chemical principles and techniques.