Question

Рассчитайте объем водорода, полученного при взаимодействии 40г кальция с водой, если выход его составляет 75% от теоретически возможного? С дано решите

Answer 1

Дано
m(Ca)=40 g
η(H2)=75%
------------------------
V(практ H2)-?
  40                                X
Ca+2H2O = Ca(OH)2+H2 M(Ca)=40 g/mol Vm=22.4L/mol
40                                  22.4
X=40*22.4 / 40 = 22.4 L
V(практ H2) = V(теор H2)*η(H2) / 100% = 22.4*75%/100% = 16.8 л
ответ 16.8 л

Answer 2

Вот насчёт уравнения реакции так себе.
там выход может быть CaO+H2, но это не точно. Но на ответ все равно не повлияет)

Answer 3

Calculating the Volume of Hydrogen Gas Produced

To calculate the volume of hydrogen gas produced when 40g of calcium reacts with water, we can use the following steps:

1. Balanced Chemical Equation: The balanced chemical equation for the reaction of calcium with water is: ``` Ca + 2H2O -> Ca(OH)2 + H2 ```

2. Molar Mass of Calcium: The molar mass of calcium (Ca) is 40.08 g/mol.

3. Molar Mass of Hydrogen: The molar mass of hydrogen (H2) is 2.016 g/mol.

4. Calculation of Moles of Calcium: We need to calculate the moles of calcium using its molar mass: ``` Moles of Ca = Mass of Ca / Molar Mass of Ca = 40g / 40.08 g/mol ≈ 0.998 mol ```

5. Calculation of Moles of Hydrogen: According to the balanced chemical equation, 1 mole of calcium produces 1 mole of hydrogen. Therefore: ``` Moles of H2 = Moles of Ca ≈ 0.998 mol ```

6. Calculation of Volume of Hydrogen Gas: We can use the ideal gas law to calculate the volume of hydrogen gas produced: ``` PV = nRT ```

Where: - P = Pressure (atm) - V = Volume (L) - n = Number of moles - R = Ideal gas constant (0.0821 L.atm/mol.K) - T = Temperature (K)

Given that the reaction occurs at standard conditions (1 atm and 273 K), we can simplify the equation to: ``` V = nRT / P = (0.998 mol)(0.0821 L.atm/mol.K)(273 K) / 1 atm ≈ 21.5 L ```

Conclusion

The volume of hydrogen gas produced when 40g of calcium reacts with water, considering a 75% yield, is approximately 21.5 liters.