Question

Даю 50 баллов!! Простое задания с расстановкой коэффициентов, в уравнениях по химии!!! C18H38+02=(равно вместо стрелки)CO2+H2O CO2+Ca(OH)2=CaCO3+H2O CS2+O2=CO2+H20 C2H6O+O2=CO2+H2O C4H10+O2=CO2+H2O CH3SH+O2=CO2+H2O+SO2 Cu+O2=CuO CuO+H2SO4=CuSO4+H2O

Answer 1

2 C18H38 + 55 O2 = 36 CO2 + 38 H2O
CO2 + Ca(OH)2 = CaCO3 + H2O
CS + 2 O2 = CO2 + SO2
C2H6O + 3 O2 = 2 CO2 + 3 H2O
2 C4H10 + 13 O2 = 8 CO2 + 10 H2O
CH3SH + 3 O2 = CO2 + 2 H2O + SO2
2 Cu + O2 = 2 CuO
CuO + H2SO4 = CuSO4 + H2O

Answer 2

Balancing Chemical Equations

To balance the given chemical equations, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's go through each equation and balance them one by one.

1. C18H38 + O2 = CO2 + H2O To balance the equation, we need to ensure that the number of carbon (C) and hydrogen (H) atoms is the same on both sides. We can start by balancing the carbon atoms first. Since there are 18 carbon atoms on the left side and only 1 carbon atom on the right side, we need to put a coefficient of 18 in front of CO2. This gives us: C18H38 + O2 = 18CO2 + H2O Now, let's balance the hydrogen atoms. There are 38 hydrogen atoms on the left side and only 2 hydrogen atoms on the right side. To balance them, we need to put a coefficient of 19 in front of H2O. This gives us the balanced equation: C18H38 + O2 = 18CO2 + 19H2O

2. Ca(OH)2 = CaCO3 + H2O In this equation, we need to balance the calcium (Ca), hydrogen (H), and oxygen (O) atoms. There is 1 calcium atom on both sides, so it is already balanced. Let's balance the hydrogen atoms next. There are 2 hydrogen atoms on the left side and only 2 hydrogen atoms on the right side, so they are already balanced. Finally, let's balance the oxygen atoms. There are 2 oxygen atoms on the left side and 3 oxygen atoms on the right side. To balance them, we need to put a coefficient of 3 in front of H2O. This gives us the balanced equation: Ca(OH)2 = CaCO3 + 3H2O

3. CS2 + O2 = CO2 + H2O To balance this equation, we need to balance the carbon (C), sulfur (S), and oxygen (O) atoms. There is 1 carbon atom on both sides, so it is already balanced. Let's balance the sulfur atoms next. There is 1 sulfur atom on the left side and 1 sulfur atom on the right side, so they are already balanced. Finally, let's balance the oxygen atoms. There are 2 oxygen atoms on the left side and 3 oxygen atoms on the right side. To balance them, we need to put a coefficient of 3/2 (or 1.5) in front of O2. This gives us the balanced equation: CS2 + 1.5O2 = CO2 + H2O

4. C2H6O + O2 = CO2 + H2O In this equation, we need to balance the carbon (C), hydrogen (H), and oxygen (O) atoms. There are 2 carbon atoms on the left side and only 1 carbon atom on the right side, so we need to put a coefficient of 2 in front of CO2. This gives us: C2H6O + O2 = 2CO2 + H2O Now, let's balance the hydrogen atoms. There are 6 hydrogen atoms on the left side and only 2 hydrogen atoms on the right side. To balance them, we need to put a coefficient of 3 in front of H2O. This gives us the balanced equation: C2H6O + O2 = 2CO2 + 3H2O

5. C4H10 + O2 = CO2 + H2O To balance this equation, we need to balance the carbon (C) and hydrogen (H) atoms. There are 4 carbon atoms on the left side and only 1 carbon atom on the right side, so we need to put a coefficient of 4 in front of CO2. This gives us: C4H10 + O2 = 4CO2 + H2O Now, let's balance the hydrogen atoms. There are 10 hydrogen atoms on the left side and only 2 hydrogen atoms on the right side. To balance them, we need to put a coefficient of 5 in front of H2O. This gives us the balanced equation: C4H10 + O2 = 4CO2 + 5H2O

6. CH3SH + O2 = CO2 + H2O + SO2 In this equation, we need to balance the carbon (C), hydrogen (H), sulfur (S), and oxygen (O) atoms. There is 1 carbon atom on both sides, so it is already balanced. Let's balance the hydrogen atoms next. There are 4 hydrogen atoms on the left side and only 2 hydrogen atoms on the right side, so we need to put a coefficient of 2 in front of H2O. This gives us: CH3SH + O2 = CO2 + 2H2O + SO2 Now, let's balance the sulfur atoms. There is 1 sulfur atom on the left side and 1 sulfur atom on the right side, so they are already balanced. Finally, let's balance the oxygen atoms. There are 2 oxygen atoms on the left side and 5 oxygen atoms on the right side. To balance them, we need to put a coefficient of 5/2 (or 2.5) in front of O2. This gives us the balanced equation: CH3SH + 2.5O2 = CO2 + 2H2O + SO2

7. Cu + O2 = CuO In this equation, we need to balance the copper (Cu) and oxygen (O) atoms. There is 1 copper atom on both sides, so it is already balanced. Let's balance the oxygen atoms next. There are 2 oxygen atoms on the left side and only 1 oxygen atom on the right side, so we need to put a coefficient of 2 in front of CuO. This gives us the balanced equation: Cu + O2 = 2CuO

8. CuO + H2SO4 = CuSO4 + H2O To balance this equation, we need to balance the copper (Cu), sulfur (S), hydrogen (H), and oxygen (O) atoms. There is 1 copper atom on both sides, so it is already balanced. Let's balance the sulfur atoms next. There is 1 sulfur atom on the left side and 1 sulfur atom on the right side, so they are already balanced. Now, let's balance the hydrogen atoms. There are 2 hydrogen atoms on the left side and only 2 hydrogen atoms on the right side, so they are already balanced. Finally, let's balance the oxygen atoms. There are 4 oxygen atoms on the left side and only 4 oxygen atoms on the right side, so they are already balanced. This equation is already balanced.

Here are the balanced chemical equations:

1. C18H38 + O2 = 18CO2 + 19H2O 2. Ca(OH)2 = CaCO3 + 3H2O 3. CS2 + 1.5O2 = CO2 + H2O 4. C2H6O + O2 = 2CO2 + 3H2O 5. C4H10 + O2 = 4CO2 + 5H2O 6. CH3SH + 2.5O2 = CO2 + 2H2O + SO2 7. Cu + O2 = 2CuO 8. CuO + H2SO4 = CuSO4 + H2O

I hope this helps! Let me know if you have any further questions.