Question

ПОМОГИ СРОЧНО. ДАЮ ВСЕ БАЛЛЫ Сбалансированное уравнение показывает реакцию карбоната натрия с соляной кислотой. Na2CO2+ 2HCl -> 2NaCl + CO2 + H2O Какая масса хлорида натрия образуется при взаимодействии 10,6 г карбоната натрия с избытком соляной кислоты?

Answer 1

Balanced Equation:

The balanced equation for the reaction between sodium carbonate and hydrochloric acid is:

Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O [[1]]

Molar Mass:

To calculate the mass of sodium chloride formed, we need to determine the number of moles of sodium carbonate reacted and then use the stoichiometry of the balanced equation.

The molar mass of sodium carbonate (Na2CO3) is calculated as follows: - 2 sodium atoms (2 x 22.99 g/mol) = 45.98 g/mol - 1 carbon atom (1 x 12.01 g/mol) = 12.01 g/mol - 3 oxygen atoms (3 x 16.00 g/mol) = 48.00 g/mol

Adding these values together, we get: 45.98 g/mol + 12.01 g/mol + 48.00 g/mol = 105.99 g/mol [[2]]

Moles of Sodium Carbonate:

To find the number of moles of sodium carbonate, we divide the given mass (10.6 g) by the molar mass of sodium carbonate:

10.6 g / 105.99 g/mol = 0.1 mol [[3]]

Stoichiometry:

According to the balanced equation, 1 mole of sodium carbonate reacts with 2 moles of hydrochloric acid to produce 2 moles of sodium chloride.

Since there is an excess of hydrochloric acid, all the sodium carbonate will react, and the number of moles of sodium chloride formed will be equal to the number of moles of sodium carbonate.

Therefore, the number of moles of sodium chloride formed is 0.1 mol.

Mass of Sodium Chloride:

To calculate the mass of sodium chloride formed, we multiply the number of moles of sodium chloride by its molar mass.

The molar mass of sodium chloride (NaCl) is calculated as follows: - 1 sodium atom (1 x 22.99 g/mol) = 22.99 g/mol - 1 chlorine atom (1 x 35.45 g/mol) = 35.45 g/mol

Adding these values together, we get: 22.99 g/mol + 35.45 g/mol = 58.44 g/mol [[4]]

Now, we can calculate the mass of sodium chloride formed:

Mass of sodium chloride = Number of moles of sodium chloride x Molar mass of sodium chloride Mass of sodium chloride = 0.1 mol x 58.44 g/mol = 5.844 g

Therefore, the mass of sodium chloride formed when 10.6 g of sodium carbonate reacts with an excess of hydrochloric acid is approximately 5.844 grams.

Please note that the actual mass may vary depending on the reaction conditions and the purity of the reactants.

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