Question

Какая соль образуется при взаимодействии 1 моль гидроксида бария с 2 моль фосфорной кислоты? Ответ пояснить, доказав вычислениями.

Answer 1

Ответ: Ва (ОН) 2+HCI

Ba (OH) CI+H20

Объяснение:

Answer 2

Formation of Salt from Barium Hydroxide and Phosphoric Acid

When 1 mole of barium hydroxide reacts with 2 moles of phosphoric acid, the following chemical equation represents the reaction:

Ba(OH)2 + H3PO4 → Ba3(PO4)2 + 2H2O

This reaction forms barium phosphate and water as products. The balanced chemical equation shows the stoichiometry of the reaction, indicating that 1 mole of barium hydroxide reacts with 2 moles of phosphoric acid to produce 1 mole of barium phosphate and 2 moles of water.

To calculate the amount of barium phosphate formed, we can use the stoichiometry of the reaction. Given that 1 mole of barium hydroxide reacts with 2 moles of phosphoric acid, the amount of barium phosphate formed can be calculated as follows:

1 mole of Ba(OH)2 reacts with 2 moles of H3PO4 to produce 1 mole of Ba3(PO4)2.

Therefore, when 1 mole of barium hydroxide reacts with 2 moles of phosphoric acid, 1 mole of barium phosphate is formed.

This calculation is based on the stoichiometry of the reaction and the balanced chemical equation, which indicates the molar ratios of the reactants and products involved in the reaction.