Question

Используя необходимые реактивы,осуществите реакции по следующим схемам: a) CO3(2-)+2H=H2O+CO2 b)Ca(2+)+CO3(2-)=CaCO3 Укажите условия протекания реакции до конца. Запишите уравнения химических реакций в молекулярной и ионной формах.

Answer 1

CaCO3+2HCl=CaCl2+H2O+CO2
2H(+)+CO3(2-)=H2O+CO2
образование воды и выделение  газа

CaCl2+H2CO3=CaCO3+2HCl
Ca(2+)+CO3(2-)=CaCO3
образование осадка

Answer 2

Reaction a) CO3(2-) + 2H+ = H2O + CO2

The reaction between carbonate ion (CO3(2-)) and hydrogen ions (H+) results in the formation of water (H2O) and carbon dioxide (CO2).

The balanced molecular equation for this reaction is:

CO3(2-) + 2H+ = H2O + CO2

To write the ionic equation, we need to consider the dissociation of the reactants and products. Carbonate ion (CO3(2-)) dissociates into one carbonate ion and two hydrogen ions:

CO3(2-) = CO3(2-)

Hydrogen ions (H+) dissociate into two hydrogen ions:

2H+ = 2H+

The ionic equation for this reaction is:

CO3(2-) + 2H+ = H2O + CO2

Reaction b) Ca(2+) + CO3(2-) = CaCO3

The reaction between calcium ion (Ca(2+)) and carbonate ion (CO3(2-)) results in the formation of calcium carbonate (CaCO3).

The balanced molecular equation for this reaction is:

**Ca(2+) +