Question

(b) Күрделі қосылыстың құрамындағы элементтердің массалық үлестері H-2,04%, S- 32,65%, 0- 65,31%-ке тең. Қосылыстың молекулалық формуласын анықтаңыз.

Answer 1

Ответ:

найдем количество элементов содержащееся в 100 г вещества

v(H) = w(H)/A(H) = 2,04/1 = 2,04 моль

v(S) = w(S)/A(S) = 32,65/32 = 1,02 моль

v(O) = w(O)/A(O) = 65,31/16 = 4,08  моль

Составим соотношение количества элементов в молях:

v(H):v(S):v(O) = 2,04:1,02:4,08.

v(H):v(S):v(O) = 2:1:4.

Формула химического соединения серная кислота  H2SO4.

Объяснение:I  hope you will enjoy the answer

Answer 2

Chemical Composition of the Compound

The chemical composition of the compound in question consists of three elements: hydrogen (H), sulfur (S), and oxygen (O). The mass percentages of these elements in the compound are as follows:

- Hydrogen (H): 2.04% - Sulfur (S): 32.65% - Oxygen (O): 65.31% [[1]]

Molecular Formula of the Compound

To determine the molecular formula of the compound, we need to consider the atomic masses of the elements involved. The atomic masses are as follows:

- Hydrogen (H): 1.00784 g/mol - Sulfur (S): 32.06 g/mol - Oxygen (O): 15.999 g/mol [[2]]

To calculate the molecular formula, we can start by assuming a 100 g sample of the compound. From the given mass percentages, we can determine the number of moles of each element in the sample:

- Hydrogen (H): (2.04 g / 1.00784 g/mol) = 2.02 mol - Sulfur (S): (32.65 g / 32.06 g/mol) = 1.02 mol - Oxygen (O): (65.31 g / 15.999 g/mol) = 4.08 mol

Next, we need to find the simplest whole number ratio of the elements in the compound. Dividing the number of moles of each element by the smallest number of moles (1.02 mol), we get the following ratios:

- Hydrogen (H): 2.02 mol / 1.02 mol = 1.98 ≈ 2 - Sulfur (S): 1.02 mol / 1.02 mol = 1 - Oxygen (O): 4.08 mol / 1.02 mol = 4

Therefore, the simplest whole number ratio of the elements in the compound is H2S4O. This is the empirical formula of the compound.

Please note that without additional information, it is not possible to determine the exact molecular formula of the compound. The empirical formula provides the simplest ratio of elements in the compound, but there could be multiple molecular formulas that correspond to this empirical formula.