Question

Знайдіть масу вуглекислого газу об'ємом 6,72 л.​

Answer 1

Дано:
V(CO2)= 6,72 л
Знайти :
m(CO2)-?
Розв’язання :
1)Оскільки відомий об’єм , то знайдемо кількість речовини за формулою:
n=V/Vm
Vm це стала ,яка дорівнює 22,4 л/моль
Звідси маємо:
n(CO2)= 6,72/ 22,4=0,3 моль
За формулою
n=m/M знайдемо m(CO2)
M(CO2)=44,01 г/моль
m(CO2)= M(CO2)* n(CO2)= 44,01*0,3=13,2 л
Відповідь: m(CO2)= 13,2 л

Answer 2

Calculating the Mass of Carbon Dioxide Gas

To find the mass of carbon dioxide gas with a volume of 6.72 L, we can use the ideal gas law equation:

PV = nRT

Where: - P = pressure - V = volume - n = number of moles - R = ideal gas constant - T = temperature

We can rearrange the equation to solve for the number of moles (n):

n = PV / RT

Given that the volume (V) is 6.72 L and assuming standard temperature and pressure (STP), we can use the following values: - Pressure (P) = 1 atm - Ideal gas constant (R) = 0.0821 L·atm/(K·mol) - Temperature (T) = 273 K

Substitute these values into the equation to find the number of moles (n).

n = (1 atm) * (6.72 L) / (0.0821 L·atm/(K·mol) * 273 K)

Calculating the value of n gives us the number of moles of carbon dioxide gas.

Conclusion

Based on the ideal gas law equation and the given volume of 6.72 L, the mass of carbon dioxide gas can be calculated using the number of moles obtained from the equation.