Question

Составить окислительно-восстановительный баланс, уровнять реакции:KMnO4+HCl->KCl+MnCl2+Cl2+H2O; MnO2+HCl->MnCl2+Cl2+H2O

Answer 1

Решение смотри в прикрепленном файле

Answer 2

Balancing Redox Reactions:

To balance the given redox reactions, we can use the half-reaction method. This involves breaking down the reaction into two half-reactions: the oxidation half-reaction and the reduction half-reaction. Then, balance each half-reaction separately and combine them to obtain the balanced overall reaction.

Balancing the First Reaction: KMnO4 + HCl -> KCl + MnCl2 + Cl2 + H2O

1. Oxidation Half-Reaction: MnO4- -> Mn2+ 2. Reduction Half-Reaction: Cl- -> Cl2

Balancing the half-reactions: 1. Oxidation Half-Reaction: 8H+ + MnO4- + 5e- -> Mn2+ + 4H2O 2. Reduction Half-Reaction: 2Cl- -> Cl2 + 2e-

Now, balance the number of electrons transferred in both half-reactions: Multiply the reduction half-reaction by 5 and the oxidation half-reaction by 2 to equalize the number of electrons in both half-reactions.

Combining the balanced half-reactions: 2KMnO4 + 16HCl -> 2KCl + 2MnCl2 + 5Cl2 + 8H2O

Balancing the Second Reaction: MnO2 + HCl -> MnCl2 + Cl2 + H2O

1. Oxidation Half-Reaction: MnO2 -> Mn2+ 2. Reduction Half-Reaction: Cl- -> Cl2

Balancing the half-reactions: 1. Oxidation Half-Reaction: 4H+ + MnO2 + 2e- -> Mn2+ + 2H2O 2. Reduction Half-Reaction: 2Cl- -> Cl2 + 2e-

Now, balance the number of electrons transferred in both half-reactions: Multiply the reduction half-reaction by 1 and the oxidation half-reaction by 2 to equalize the number of electrons in both half-reactions.

Combining the balanced half-reactions: MnO2 + 4HCl -> MnCl2 + Cl2 + 2H2O

These are the balanced redox reactions for the given chemical equations.

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