Question

Какой объем водорода выделяется в результате реакции 1,2 магния с салярной кислотой.СРОЧНО!!!!!!!!!!!

Answer 1

Mg + 2HCl = MgCl2 + H2

- Рассчитаем количество вещества магния:

n = m/M = 1,2г/24г/моль = 0,05моль

- По уравнению реакции:

n(H2) = n(Mg) = 0,05моль

- V = Vm*n = 0,05моль*22,4л/моль = 1,12л

Answer 2

Reaction of Magnesium with Sulfuric Acid

When magnesium reacts with sulfuric acid, the following chemical reaction takes place:

1,2 Mg + H2SO4 → MgSO4 + H2

Volume of Hydrogen Gas Produced

The balanced chemical equation for the reaction shows that 1 mole of magnesium reacts with 1 mole of sulfuric acid to produce 1 mole of hydrogen gas. Therefore, the volume of hydrogen gas produced can be calculated using the ideal gas law, which states that 1 mole of any gas at standard temperature and pressure (STP) occupies 22.4 liters.

Given that 1 mole of any gas at STP occupies 22.4 liters, the volume of hydrogen gas produced can be calculated based on the number of moles of hydrogen gas produced.

Calculation

The molar volume of a gas at STP is 22.4 liters/mol. Since 1 mole of magnesium reacts with sulfuric acid to produce 1 mole of hydrogen gas, the volume of hydrogen gas produced can be calculated as follows:

Volume of hydrogen gas = Number of moles of hydrogen gas × Molar volume at STP

Conclusion

To determine the exact volume of hydrogen gas produced, it is necessary to know the quantity of magnesium and sulfuric acid used in the reaction. Once the number of moles of hydrogen gas is known, the volume of hydrogen gas produced can be calculated using the molar volume of a gas at STP.

If you have the specific quantities of magnesium and sulfuric acid used in the reaction, I can help you calculate the volume of hydrogen gas produced.