Question

Помогите решить задачу по химии!! После пропускания 11.2 л сернистого газа через раствор гидроксида натрия получили раствор массой 1042 г. Вычислите массовую долю соли в образовавшемся растворе.

Answer 1

Ответ:

Тут будет два решения, поскольку не указан процент содержания гидрооксида натрия или какая соль образуется, поэтому соль может образоваться как средняя, так и кислая.

SO2 + NаOH =  NaHSO3

n(SO2)=11.2/22.4=0.5 моль

n(SO2)=n(NaHSO3)

m(NaHSO3)=0.5*104=52 грамма

W(NaHSO3)=52/1042=0,0499 - 4.99%

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SO2 + 2NaOH = Na2SO3 + H2O

n(SO2)=n(Na2SO3)

m(Na2SO3)=0.5*126=63 грамма

W(Na2SO3)=63/1042=0,06 - 6%

Answer 2

Solution to the Chemistry Problem:

To solve this problem, we can use the concept of stoichiometry to determine the mass fraction of the salt in the resulting solution.

Given: - Volume of sulfur dioxide gas (V) = 11.2 L - Mass of resulting solution = 1042 g

Step 1: Convert Volume of Gas to Moles: The first step is to convert the volume of sulfur dioxide gas to moles using the ideal gas law, which states that 1 mole of any gas occupies 22.4 liters at standard temperature and pressure (STP).

The number of moles of sulfur dioxide gas (n) can be calculated using the formula: \[ n = \frac{V}{V_m} \] where V is the volume of the gas and \( V_m \) is the molar volume of the gas at STP.

Using this formula, we can calculate the number of moles of sulfur dioxide gas.

Step 2: Determine the Reaction and Calculate the Mass of Salt: The reaction between sulfur dioxide gas and sodium hydroxide solution can be represented as: \[ SO_2 + 2NaOH \rightarrow Na_2SO_3 + H_2O \]

From the balanced chemical equation, we can see that 1 mole of sulfur dioxide reacts with 2 moles of sodium hydroxide to produce 1 mole of sodium sulfite.

Using the molar mass of sodium sulfite, we can calculate the mass of the salt produced.

Step 3: Calculate the Mass Fraction of the Salt: Finally, we can calculate the mass fraction of the salt in the resulting solution using the formula: \[ \text{Mass fraction} = \frac{\text{Mass of salt}}{\text{Total mass of solution}} \times 100\% \]

By substituting the calculated values into this formula, we can determine the mass fraction of the salt in the solution.

I will now proceed to calculate the values and provide the solution.