Question

ДопоможітьBa→BaO→Ba(OH)2S→SO2→H2SO3→SO2​

Answer 1

Ответ:

не впевненна що правильно, але наче так

Answer 2

The given sequence of reactions involves the transformation of barium (Ba) into sulfur dioxide (SO2) and then into sulfurous acid (H2SO3). Let's break down each step of the reaction sequence:

1. Ba → BaO: - In this step, barium (Ba) reacts with oxygen (O) to form barium oxide (BaO). - The balanced chemical equation for this reaction is: 2Ba + O2 → 2BaO.

2. BaO → Ba(OH)2: - In this step, barium oxide (BaO) reacts with water (H2O) to form barium hydroxide (Ba(OH)2). - The balanced chemical equation for this reaction is: BaO + H2O → Ba(OH)2.

3. Ba(OH)2 → Ba(OH)2S: - In this step, barium hydroxide (Ba(OH)2) reacts with sulfur (S) to form barium hydroxide sulfide (Ba(OH)2S). - The balanced chemical equation for this reaction is: Ba(OH)2 + S → Ba(OH)2S.

4. Ba(OH)2S → SO2: - In this step, barium hydroxide sulfide (Ba(OH)2S) decomposes to form sulfur dioxide (SO2). - The balanced chemical equation for this reaction is: Ba(OH)2S → SO2 + H2O.

5. SO2 → H2SO3: - In this step, sulfur dioxide (SO2) reacts with water (H2O) to form sulfurous acid (H2SO3). - The balanced chemical equation for this reaction is: SO2 + H2O → H2SO3.

The overall reaction sequence can be summarized as follows: 2Ba + O2 → 2BaO BaO + H2O → Ba(OH)2 Ba(OH)2 + S → Ba(OH)2S Ba(OH)2S → SO2 + H2O SO2 + H2O → H2SO3

Please note that the given reaction sequence is a simplified representation, and the actual reaction conditions and stoichiometry may vary depending on the specific experimental setup or reaction conditions.

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