Question

(b) Запишите, сбалансированное уравнение реакции полного сгорания бутана, используя молекулярные формулы.

Answer 1

Ответ:

b) C4H10 - бутан

2C4H10+13O2 → 8CO2+10H2O

Вот полностью сбалансированное уравнение реакции полного сгорания бутана

Answer 2

Butane (C4H10) undergoes complete combustion in the presence of excess oxygen (O2) to form carbon dioxide (CO2) and water (H2O).

The balanced equation for the complete combustion of butane is:

2C4H10 + 13O2 → 8CO2 + 10H2O

In this equation, each molecule of butane (C4H10) reacts with 13 molecules of oxygen (O2) to produce 8 molecules of carbon dioxide (CO2) and 10 molecules of water (H2O).

This equation is balanced because the number of atoms of each element is the same on both sides of the equation. On the left side, we have 2 carbon (C) atoms, 10 hydrogen (H) atoms and 26 oxygen (O) atoms. On the right side, we also have 2 carbon (C) atoms, 10 hydrogen (H) atoms and 26 oxygen (O) atoms.

Balancing the equation ensures that the law of conservation of mass is satisfied, as no atoms are created or destroyed during the reaction.