Question

Встанови елемент 3 періоду та обчисли молярну масу леткої сполуки з Гідрогеном, яка відповідає загальній формулі RH3

Answer 1

елемент: Фосфор P

M(PH3) = 31+3 = 34 г/моль

Answer 2

Element of the 3rd Period and Molar Mass Calculation

The element in the 3rd period that corresponds to the general formula RH3 is boron (B). Boron is a chemical element with the atomic number 5 and the symbol B. It is a metalloid and is found in group 13 of the periodic table.

To calculate the molar mass of the volatile compound with hydrogen that corresponds to the general formula RH3, we need to know the molar mass of the element R. Since R is not specified in the question, we cannot provide an exact molar mass value. However, we can provide a general method to calculate the molar mass of any compound.

To calculate the molar mass of a compound, we need to know the atomic masses of the elements present in the compound. The atomic masses can be found on the periodic table. We then multiply the atomic mass of each element by the number of atoms of that element in the compound and sum up the values.

For example, if R is boron (B), the molar mass of the compound RH3 would be calculated as follows:

- Atomic mass of boron (B) = 10.81 g/mol (approximately) [[1]] - Number of boron atoms in RH3 = 1 - Number of hydrogen atoms in RH3 = 3 - Molar mass of RH3 = (Atomic mass of boron × number of boron atoms) + (Atomic mass of hydrogen × number of hydrogen atoms) - Molar mass of RH3 = (10.81 g/mol × 1) + (1.01 g/mol × 3) - Molar mass of RH3 = 10.81 g/mol + 3.03 g/mol - Molar mass of RH3 = 13.84 g/mol (approximately)

Please note that the molar mass value provided above is an approximate value and may vary depending on the specific compound and its isotopic composition.

I hope this helps! Let me know if you have any further questions.