Question

Рівняння реакції сполучення - горіння простої речовини: а) СаО + Н2О = Са(ОН)2б) 4Li + O2 = 2Li2Oв) 2СО + О2 = 2СО2г) 2РН3 + 4О2 = Р2О5 + 3Н2О​

Answer 1

Ответ:

Правильный ответ б) 4Li+O2=2Li2O

Answer 2

Equation of the Combustion Reaction of Simple Substances:

The equation of the combustion reaction of simple substances can be represented by the following examples:

a) CaO + H2O = Ca(OH)2 - Calcium oxide (CaO) reacts with water (H2O) to form calcium hydroxide (Ca(OH)2) [[1]].

b) 4Li + O2 = 2Li2O - Four lithium atoms (Li) react with one molecule of oxygen (O2) to form two molecules of lithium oxide (Li2O) [[2]].

c) 2CO + O2 = 2CO2 - Two molecules of carbon monoxide (CO) react with one molecule of oxygen (O2) to form two molecules of carbon dioxide (CO2) [[3]].

d) 2NH3 + 4O2 = P2O5 + 3H2O - Two molecules of ammonia (NH3) react with four molecules of oxygen (O2) to form phosphorus pentoxide (P2O5) and three molecules of water (H2O) [[4]].

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