Question

1)HCL+Mg=MgCL2+H2 2)AL+CL2=ALCL3 3)CuO+H2=Cu+H2O 4)Cu+HNO3=Cu(NO3)2+NO2+H2O ПОжалуйста прошу решиить уравнение реакции.как окислительно-восстановительные

Answer 1

1)2HCL+Mg=MgCL2+H2

Mg(0)-2e=Mg(+2) в-ль

2H(+)+2e=H2(0) ок-ль

 

2)2AL+3CL2=2ALCL3

Al(0)-3e=Al(+3) в-ль

Cl2(0)+2e=2Cl(-) ок-ль

 

3)CuO+H2=Cu+H2O

Сu(+2)+2e=Cu(0) ок-ль

H2(0)-2e=2H(+)  в-ль

 

4)Cu+4HNO3=Cu(NO3)2+2NO2+2H2O

Cu(0)-2e=Cu(+2) в-ль

N(+5)+1e=N(+4)  ок-ль

 

 

В последнем уравнении можно использовать метод полуреакций (для азота)

NO3(-)+2H(+)+1e=NO2(0)+H2O(0)

 

В скобочках степени окисления

 

Answer 2

Balancing Chemical Equations:

1) HCl + Mg = MgCl2 + H2

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

The balanced equation is:

2HCl + Mg = MgCl2 + H2

2) Al + Cl2 = AlCl3

The balanced equation is:

2Al + 3Cl2 = 2AlCl3

3) CuO + H2 = Cu + H2O

The balanced equation is:

CuO + H2 = Cu + H2O

4) Cu + HNO3 = Cu(NO3)2 + NO2 + H2O

The balanced equation is:

3Cu + 8HNO3 = 3Cu(NO3)2 + 2NO + 4H2O

Oxidation-Reduction (Redox) Reactions:

In an oxidation-reduction (redox) reaction, there is a transfer of electrons between reactants. One reactant undergoes oxidation (loses electrons) while another reactant undergoes reduction (gains electrons).

Let's analyze the given reactions to identify the oxidizing and reducing agents:

1) HCl + Mg = MgCl2 + H2

In this reaction, magnesium (Mg) is oxidized from an oxidation state of 0 to +2, while hydrogen (H) is reduced from an oxidation state of +1 to 0. Therefore, magnesium is the reducing agent, and hydrogen is the oxidizing agent.

2) Al + Cl2 = AlCl3

In this reaction, aluminum (Al) is oxidized from an oxidation state of 0 to +3, while chlorine (Cl) is reduced from an oxidation state of 0 to -1. Therefore, aluminum is the reducing agent, and chlorine is the oxidizing agent.

3) CuO + H2 = Cu + H2O

In this reaction, copper(II) oxide (CuO) is reduced to copper (Cu), while hydrogen (H2) is oxidized to water (H2O). Therefore, copper(II) oxide is the oxidizing agent, and hydrogen is the reducing agent.

4) Cu + HNO3 = Cu(NO3)2 + NO2 + H2O

In this reaction, copper (Cu) is oxidized from an oxidation state of 0 to +2, while nitric acid (HNO3) is reduced. Therefore, copper is the reducing agent, and nitric acid is the oxidizing agent.

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