Question

Помогите пжлста срочно это две задачи по химии на тему:Классы неорганических соединений 1) Дано: н.у. , m ( HCl ) = 55 г Найти: V -? 2) Дано: m ( Na2CO3 ) = 42 г Найти: N-?

Answer 1

Ответ:

1) V (HCl) = 33,6 л

2) N(Na2CO3) = 2,35 × 10^ -23

Объяснение:

1) n = m/M

n (HCl) = 55 г / 36,5 г/моль = 1,5 моль

V (HCl) = n × Vm = 1,5 × 22,4 = 33,6 л

2) n (Na2CO3) = 42 г / 106 г/моль = 0,39 моль

N = n × Na

N (Na2CO3) = 0,39 × 6,02 × 10 ^ -23 = 2,35 × 10^ -23

Answer 2

Classes of Inorganic Compounds

Inorganic compounds are substances that do not contain carbon-hydrogen (C-H) bonds. They are classified into several categories based on their chemical composition and properties. Some common classes of inorganic compounds include acids, bases, salts, and oxides.

Task 1: Finding the Volume (V) of HCl

The given information for the first task is: - m (mass of HCl) = 55 g

To find the volume (V) of HCl, we need to use the formula:

V = m / ρ

where: - V is the volume of the substance - m is the mass of the substance - ρ is the density of the substance

To find the density of HCl, we can refer to the search results.

According to the search results, the density of hydrochloric acid (HCl) is approximately 1.18 g/cm³ [[1]].

Now we can substitute the given values into the formula to find the volume:

V = 55 g / 1.18 g/cm³

Calculating this expression, we find that the volume of HCl is approximately 46.61 cm³.

Therefore, the volume (V) of HCl is approximately 46.61 cm³.

Task 2: Finding the Number of Moles (N) of Na2CO3

The given information for the second task is: - m (mass of Na2CO3) = 42 g

To find the number of moles (N) of Na2CO3, we need to use the formula:

N = m / M

where: - N is the number of moles of the substance - m is the mass of the substance - M is the molar mass of the substance

To find the molar mass of Na2CO3, we can refer to the search results.

According to the search results, the molar mass of sodium carbonate (Na2CO3) is approximately 105.99 g/mol [[2]].

Now we can substitute the given values into the formula to find the number of moles:

N = 42 g / 105.99 g/mol

Calculating this expression, we find that the number of moles of Na2CO3 is approximately 0.396 mol.

Therefore, the number of moles (N) of Na2CO3 is approximately 0.396 mol.

I hope this helps! Let me know if you have any further questions.