Question

НУ ПОЖАЛУЙСТА ПОМОГИТЕ С ЗАДАНИЕМ, ХАРЭ ВОРОВАТЬ ОТВЕТЫ С ДРУГИХ ЗАДАЧ!!!! ДАЮ 50 БАЛЛОВ!!!! Хватит ли 2,8 л кислорода для полного сжигания 8 г фосфора, если в результате образуется оксид серы 4? Если кислорода недостаточно, рассчитайте необходимый объем (условия нормальные) (а)Уравнение химической реакции горения серы в кислороде P+O2=P2O5 (I)Вычислите количество вещества фосфора (II)Вычислите количества вещества кислорода (III)Вычислите объем (н.у) кислорода, применяя Закон Авогадро (b)Ответ:________________

Answer 1

Ответ:

Для начала рассчитаем количества  серы и кислорода.

n(O₂)=2.8/22.4=0.125 моль;

n(S)=8/32=0.25 моль;

Сера в избытке, поэтому решаем задачу по недостатку.

Чтобы прореагировала вся сера, потребуется ещё такое количество кислорода. Значит в сумме необходимо 0.25 моль кислорода.

V(O₂)необходимого=0.25*22.4=5.6 дм³;

I) n(S)=0.25 моль;

II) n(O₂)=0.125 моль;

III) V=n*Vm=0.125*22.4=2.8 дм³.

Answer 2

Calculation of Oxygen Required for Complete Combustion of Phosphorus

To determine whether 2.8 L of oxygen is sufficient for the complete combustion of 8 g of phosphorus, we need to calculate the stoichiometric ratio between phosphorus and oxygen in the reaction. The balanced chemical equation for the combustion of phosphorus in oxygen is:

P4 + 5O2 -> P4O10

From the equation, we can see that 1 mole of phosphorus reacts with 5 moles of oxygen to produce 1 mole of P4O10. To calculate the amount of oxygen required, we need to convert the mass of phosphorus to moles and then use the stoichiometric ratio.

Calculation Steps:

(I) Calculation of the Amount of Phosphorus:

To calculate the amount of phosphorus, we need to convert the given mass of phosphorus (8 g) to moles using its molar mass.

The molar mass of phosphorus (P) is approximately 31 g/mol.

Number of moles of phosphorus = Mass of phosphorus / Molar mass of phosphorus Number of moles of phosphorus = 8 g / 31 g/mol

(II) Calculation of the Amount of Oxygen:

Using the stoichiometric ratio from the balanced equation, we can determine the amount of oxygen required.

From the equation, we know that 1 mole of phosphorus reacts with 5 moles of oxygen.

Number of moles of oxygen = Number of moles of phosphorus * (5 moles of oxygen / 1 mole of phosphorus)

(III) Calculation of the Volume of Oxygen:

To calculate the volume of oxygen at standard conditions (n.у), we can use Avogadro's Law, which states that equal volumes of gases at the same temperature and pressure contain an equal number of molecules.

1 mole of any gas occupies 22.4 L at standard conditions (n.у).

Volume of oxygen = Number of moles of oxygen * 22.4 L/mol

Calculation Results:

Using the given values and the calculations above, we can determine the following:

(I) The amount of phosphorus: - Number of moles of phosphorus = 8 g / 31 g/mol

(II) The amount of oxygen: - Number of moles of oxygen = (8 g / 31 g/mol) * (5 moles of oxygen / 1 mole of phosphorus)

(III) The volume of oxygen: - Volume of oxygen = (8 g / 31 g/mol) * (5 moles of oxygen / 1 mole of phosphorus) * 22.4 L/mol

Please perform the calculations using the given values and formulas to obtain the final answer.