Question

Сколько метров кубических кислорода при нормальных условиях будет израсходовано на сжигание газовой смеси, состоящей из 75%метана, 15%этана и 5%водорода

Answer 1

CH4+2O2=CO2+2H20
  по уравнению
0,75м3-хм3О2 
1---           2   х=0,75*2/1=1,5м3
условно примем объем смеси за 1 м3
, тогда метана 0,75м3,  этана 0,15 м3, водорода 0,05м3
2C2H6+7O2=4CO2+6H2O
0.15-x
2-3          x=0.15*3/2=0.225m3
2H2+O2=2H2O
0.05-x
2-1       x=0.5*1/2=0.025m3
всего 1,5+0,225+0,025=1,75

Answer 2

Calculation of Oxygen Consumption for Burning Gas Mixture

To calculate the amount of oxygen consumed when burning a gas mixture, we need to know the composition of the mixture and the stoichiometric ratio of the combustion reaction. In this case, the gas mixture consists of 75% methane, 15% ethane, and 5% hydrogen.

The balanced combustion reaction for methane (CH4), ethane (C2H6), and hydrogen (H2) with oxygen (O2) can be represented as follows:

Methane (CH4): CH4 + 2O2 -> CO2 + 2H2O

Ethane (C2H6): C2H6 + 7/2O2 -> 2CO2 + 3H2O

Hydrogen (H2): 2H2 + O2 -> 2H2O

To calculate the amount of oxygen consumed, we need to determine the stoichiometric coefficients for each gas in the mixture and then calculate the total amount of oxygen required.

Calculation Steps:

1. Calculate the amount of oxygen required for each gas in the mixture: - For methane (CH4): 75% of the gas mixture - For ethane (C2H6): 15% of the gas mixture - For hydrogen (H2): 5% of the gas mixture

2. Calculate the amount of oxygen required for each gas using the stoichiometric coefficients: - For methane (CH4): 1 mole of CH4 requires 2 moles of O2 - For ethane (C2H6): 1 mole of C2H6 requires 7/2 moles of O2 - For hydrogen (H2): 2 moles of H2 require 1 mole of O2

3. Calculate the total amount of oxygen required by multiplying the amount of each gas by the stoichiometric coefficient and summing them up.

Let's perform the calculations:

1. Calculate the amount of each gas in the mixture: - Methane (CH4): 75% of the gas mixture = 0.75 - Ethane (C2H6): 15% of the gas mixture = 0.15 - Hydrogen (H2): 5% of the gas mixture = 0.05

2. Calculate the amount of oxygen required for each gas: - Methane (CH4): 0.75 * 2 = 1.5 moles of O2 - Ethane (C2H6): 0.15 * (7/2) = 0.525 moles of O2 - Hydrogen (H2): 0.05 * 1 = 0.05 moles of O2

3. Calculate the total amount of oxygen required: - Total oxygen required = 1.5 + 0.525 + 0.05 = 2.075 moles of O2

Therefore, when burning the given gas mixture, approximately 2.075 moles of oxygen will be consumed.

Please note that this calculation assumes ideal conditions and does not take into account any other factors that may affect the combustion process.