Question

Какое количество вещества хлорида бария образуется при взаимодействии 4,5 г гидроксида бария с соляной кислотой. (Срочно, пожалуйста)❤❤❤​

Answer 1

Ответ:Ba(OH)2+2HCL=BaCl2+2H2O

n(Ba(OH))2=4,5÷171=0,026моль

m(BaCl2)=0,026×208=5,408грам

Объяснение:

Answer 2

Calculation of the Amount of Barium Chloride Formed

To determine the amount of barium chloride formed when 4.5 grams of barium hydroxide reacts with hydrochloric acid, we need to consider the balanced chemical equation for the reaction:

Ba(OH)2 + 2HCl -> BaCl2 + 2H2O

From the balanced equation, we can see that 1 mole of barium hydroxide reacts with 2 moles of hydrochloric acid to produce 1 mole of barium chloride.

To calculate the amount of barium chloride formed, we need to convert the given mass of barium hydroxide to moles using its molar mass, and then use the mole ratio from the balanced equation to determine the moles of barium chloride formed.

The molar mass of barium hydroxide (Ba(OH)2) is calculated as follows: Ba: 1 atom x 137.33 g/mol = 137.33 g/mol O: 2 atoms x 16.00 g/mol = 32.00 g/mol H: 2 atoms x 1.01 g/mol = 2.02 g/mol

Total molar mass of Ba(OH)2 = 137.33 g/mol + 32.00 g/mol + 2.02 g/mol = 171.35 g/mol

Now, we can calculate the number of moles of barium hydroxide: moles of Ba(OH)2 = mass / molar mass = 4.5 g / 171.35 g/mol = 0.0263 mol

According to the balanced equation, 1 mole of barium hydroxide reacts with 1 mole of barium chloride. Therefore, the number of moles of barium chloride formed is also 0.0263 mol.

To convert the moles of barium chloride to grams, we need to multiply the number of moles by its molar mass. The molar mass of barium chloride (BaCl2) is calculated as follows: Ba: 1 atom x 137.33 g/mol = 137.33 g/mol Cl: 2 atoms x 35.45 g/mol = 70.90 g/mol

Total molar mass of BaCl2 = 137.33 g/mol + 70.90 g/mol = 208.23 g/mol

Now, we can calculate the mass of barium chloride formed: mass of BaCl2 = moles of BaCl2 x molar mass = 0.0263 mol x 208.23 g/mol = 5.46 g

Therefore, when 4.5 grams of barium hydroxide reacts with hydrochloric acid, approximately 5.46 grams of barium chloride is formed.

Note: The above calculation assumes that the reaction goes to completion and that there are no other limiting factors or side reactions.