Question

Помогите решить задачу по химии. Для приготовления десертов кладут 120 грамм мёда на 1 литр воды. Вычислите массовую долю растворенного вещества в растворе.

Answer 1

Растворенное вещество- 120г
Растворитель-1л
W%( растворенного вещества)-?

1л=1000гр
1000гр+120гр=1120гр
1120гр-100%
120гр-Х%
Х%=(120гр×100%)/1120гр
Х=10,7%

Answer 2

Calculation of the Mass Fraction of the Solute in the Solution

To calculate the mass fraction of the solute in the solution, we need to determine the mass of the solute (honey) and the total mass of the solution (honey + water).

Given: - Mass of honey = 120 grams - Volume of water = 1 liter

To find the mass of the solution, we need to convert the volume of water from liters to grams. The density of water is 1 gram per milliliter (g/mL) or 1000 grams per liter (g/L).

Using the conversion factor, we can calculate the mass of the solution as follows:

Mass of solution = Mass of honey + Mass of water

Mass of solution = 120 grams + (1 liter * 1000 grams/liter)

Mass of solution = 120 grams + 1000 grams

Mass of solution = 1120 grams

Now, we can calculate the mass fraction of the solute (honey) in the solution using the formula:

Mass fraction = (Mass of solute / Mass of solution) * 100

Mass fraction = (120 grams / 1120 grams) * 100

Mass fraction ≈ 10.71%

Therefore, the mass fraction of the solute (honey) in the solution is approximately 10.71%.

Please note that the values used in this calculation are based on the information provided in the question.