Question

В 2 реакциях определить состав эквивалента и фактор эквивалентности для Н3РО4 и КМnО4: СаСО3 + Н3РО4 = СаНРО4 + СО2 + Н2О 2КМnО4 + 16НСl = 2МnСl2 + 5Сl2 + 2КСl + 8Н2О

Answer 1

1. Н3РО4
а) fЭ = 1/3,
б) Э = 1/3{Н3РО4},
в) МЭ = fЭ•М(Н3РО4) = 1/3(3,0 + 31,0 + 4• 16,0) = 98,0/3 = 32,7 г/моль

Answer 2

Reaction 1: СаСО3 + Н3РО4 = СаНРО4 + СО2 + Н2О

In this reaction, calcium carbonate (СаСО3) reacts with nitric acid (Н3РО4) to form calcium nitrate (СаНРО4), carbon dioxide (СО2), and water (Н2О).

The composition of the reaction can be determined as follows: - Reactant 1: Calcium carbonate (СаСО3) - Reactant 2: Nitric acid (Н3РО4) - Product 1: Calcium nitrate (СаНРО4) - Product 2: Carbon dioxide (СО2) - Product 3: Water (Н2О)

The factor of equivalence (also known as stoichiometric coefficient) for each component can be determined by balancing the equation. The balanced equation for this reaction is:

CaCO3 + 2HNO3 → Ca(NO3)2 + CO2 + H2O

From the balanced equation, we can determine the factor of equivalence for each component: - Reactant 1 (СаСО3): 1 - Reactant 2 (Н3РО4): 2 - Product 1 (СаНРО4): 1 - Product 2 (СО2): 1 - Product 3 (Н2О): 1

Therefore, the factor of equivalence for Н3РО4 in this reaction is 2.

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