Question

Смешали раствор с массовой доли соли 13% №1, содержащий хлорид меди массой 600 г (плотность раствора 0.9 г/мл) и раствор №2, содержащий 130 г гидроксида натрия и 870 мл воды в результате чего образовался раствор №3. Определите массовую долю соли в полученном растворе, запишите протекающую химическую реакцию и определите какого из реагентов было в избытке

Answer 1

Ответ:

4,4%

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Answer 2

Calculation of the Mass Fraction of Salt in the Solution

To determine the mass fraction of salt in the resulting solution, we need to calculate the masses of salt and the total solution.

Given: - Solution #1 contains 13% salt (mass fraction). - Solution #1 contains 600 g of copper chloride (CuCl₂) with a density of 0.9 g/mL. - Solution #2 contains 130 g of sodium hydroxide (NaOH) and 870 mL of water.

To calculate the mass of salt in Solution #1, we can use the mass fraction:

Mass of salt in Solution #1 = Mass of Solution #1 * Mass fraction of salt in Solution #1

The mass of Solution #1 can be calculated using its density:

Mass of Solution #1 = Volume of Solution #1 * Density of Solution #1

The volume of Solution #1 can be calculated using the given mass and density:

Volume of Solution #1 = Mass of Solution #1 / Density of Solution #1

Now, let's calculate the mass of salt in Solution #1:

Mass of salt in Solution #1 = (Mass of Solution #1 * Mass fraction of salt in Solution #1)

Next, let's calculate the mass of Solution #2:

Mass of Solution #2 = Mass of sodium hydroxide (NaOH) + Mass of water

Finally, we can calculate the mass fraction of salt in the resulting solution:

Mass fraction of salt in the resulting solution = (Mass of salt in Solution #1 + Mass of salt in Solution #2) / (Mass of Solution #1 + Mass of Solution #2)

Let's calculate the values step by step.

Calculation Steps:

1. Calculate the mass of Solution #1: - Density of Solution #1 = 0.9 g/mL - Volume of Solution #1 = Mass of Solution #1 / Density of Solution #1 - Volume of Solution #1 = 600 g / 0.9 g/mL - Volume of Solution #1 = 666.67 mL

2. Calculate the mass of salt in Solution #1: - Mass of salt in Solution #1 = Volume of Solution #1 * Mass fraction of salt in Solution #1 - Mass of salt in Solution #1 = 666.67 mL * 0.13 - Mass of salt in Solution #1 = 86.67 g

3. Calculate the mass of Solution #2: - Mass of Solution #2 = Mass of sodium hydroxide (NaOH) + Mass of water - Mass of Solution #2 = 130 g + 870 mL * 1 g/mL - Mass of Solution #2 = 130 g + 870 g - Mass of Solution #2 = 1000 g

4. Calculate the mass fraction of salt in the resulting solution: - Mass fraction of salt in the resulting solution = (Mass of salt in Solution #1 + Mass of salt in Solution #2) / (Mass of Solution #1 + Mass of Solution #2) - Mass fraction of salt in the resulting solution = (86.67 g + 0 g) / (600 g + 1000 g) - Mass fraction of salt in the resulting solution = 86.67 g / 1600 g - Mass fraction of salt in the resulting solution ≈ 0.0542 or 5.42%

Therefore, the mass fraction of salt in the resulting solution is approximately 5.42%.

Chemical Reaction and Excess Reactant:

To determine the chemical reaction and the excess reactant, we need more information about the reactants and their stoichiometry. Unfortunately, the provided information does not specify the reactants involved or their stoichiometry. Please provide additional details about the reactants and their quantities so that we can determine the chemical reaction and identify the excess reactant.