Question

Вычислите объем(V) и массу(m) водорода (H), полученного в результате разложения одного кг воды(H2O)

Answer 1

Уравнение реакции:
2H2O ⇒ 2H2 + O2
Согласно закону эквивалентов имеем:
 - для объема:
   $\frac{m_{(H_2O)}}{n_{(H_2O)} * M_{(H_2O)}} = \frac{V_{H_2}}{n_{H_2} * V_m}$
Отсюда V(H2) = 1000 * 2 * 22,4 / (2 * 18) = 1244,44 л

 - для массы:
  $\frac{m_{(H_2O)}}{n_{(H_2O)} * M_{(H_2O)}} = \frac{m_{H_2}}{n_{H_2} * M_{H_2}}$
Отсюда m(H2) = 1000 * 2 * 2 / (2 * 18) = 111,11 г

Ответ: 1244,44 л; 111,11 г

Answer 2

Calculating the Volume and Mass of Hydrogen Obtained from the Decomposition of Water (H2O)

To calculate the volume (V) and mass (m) of hydrogen (H) obtained from the decomposition of one kilogram of water (H2O), we can use the chemical equation for the decomposition of water into hydrogen and oxygen:

2H2O → 2H2 + O2

First, let's calculate the volume of hydrogen gas produced (V) and then determine its mass (m).

Volume of Hydrogen Gas (V)

The molar volume of any gas at standard temperature and pressure (STP) is 22.4 liters per mole. Using this information, we can calculate the volume of hydrogen gas produced.

From Source we have the following information: - 2H2O = 2H2 + O2 - 1 mole of water (H2O) produces 2 moles of hydrogen gas (H2) - V = 7.5 * 22.4 = 168 liters

So, the volume of hydrogen gas produced (V) is 168 liters.

Mass of Hydrogen Gas (m)

The molar mass of hydrogen (H2) is 2 grams per mole.

From Source we have the following information: - 2H2 + O2 = 2H2O - 1 mole of water (H2O) produces 2 moles of hydrogen gas (H2) - 2 grams of hydrogen gas (H2) per mole

Using this information, we can calculate the mass of hydrogen gas produced: - 2 moles of hydrogen gas (H2) = 2 * 2 = 4 grams

Therefore, the mass of hydrogen gas produced (m) is 4 grams.

In summary, the volume (V) of hydrogen gas obtained from the decomposition of one kilogram of water (H2O) is 168 liters, and the mass (m) of hydrogen gas obtained is 4 grams.