Question

11.2 Добери коефіцієнти у схемах реакцій. HgO→ _Hg + __ Oz NaNO3 → _NaNO2 + __ O2 _Fe2O3 + Н,О Fe(OH)3 → > Укажи тип реакцій.​

Answer 1

Відповідь:

HgO→ Hg + O2 (розклад)

NaNO3 → NaNO2 + O2 (розклад)

Fe2O3 + 3H2O → 2Fe(OH)3 (двогатункова заміна)

У першій реакції коефіцієнти: 2, 1

У другій реакції коефіцієнти: 2, 2

У третій реакції коефіцієнти: 1, 6

Пояснення:

Answer 2

Balancing Chemical Equations

To balance the chemical equations provided, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's balance each equation step by step.

1. HgO → Hg + O₂ - To balance the equation, we need to ensure that the number of mercury (Hg) atoms and oxygen (O) atoms is the same on both sides. - The coefficient for HgO is 1, so we have 1 Hg and 1 O on the left side. - To balance the equation, we need to put a coefficient of 2 in front of Hg on the right side to have 2 Hg atoms. - The balanced equation is: HgO → 2Hg + O₂.

2. NaNO₃ → NaNO₂ + O₂ - To balance the equation, we need to ensure that the number of sodium (Na), nitrogen (N), and oxygen (O) atoms is the same on both sides. - The coefficient for NaNO₃ is 1, so we have 1 Na, 1 N, and 3 O on the left side. - To balance the equation, we need to put a coefficient of 2 in front of NaNO₂ on the right side to have 2 Na, 2 N, and 4 O atoms. - The balanced equation is: 2NaNO₃ → 2NaNO₂ + O₂.

3. Fe₂O₃ + H₂O → Fe(OH)₃ - To balance the equation, we need to ensure that the number of iron (Fe), oxygen (O), and hydrogen (H) atoms is the same on both sides. - The coefficient for Fe₂O₃ is 1, so we have 2 Fe and 3 O on the left side. - To balance the equation, we need to put a coefficient of 2 in front of Fe(OH)₃ on the right side to have 2 Fe, 6 O, and 6 H atoms. - The balanced equation is: Fe₂O₃ + 3H₂O → 2Fe(OH)₃.

Types of Reactions

Now let's determine the types of reactions for each balanced equation:

1. HgO → 2Hg + O₂ - This is a decomposition reaction, where a single compound breaks down into two or more simpler substances.

2. 2NaNO₃ → 2NaNO₂ + O₂ - This is also a decomposition reaction, where a compound breaks down into two or more simpler substances.

3. Fe₂O₃ + 3H₂O → 2Fe(OH)₃ - This is a double displacement reaction, where the cations and anions of two compounds switch places to form new compounds.

I hope this helps! Let me know if you have any further questions.