Question

Составьте задачу на основе реакции нейтрализации,если известна масса одного из вступающих в реакцию веществ.Решите задачу

Answer 1

Вычислите массу соли, образовавшейся при взаимодействии избытка серной кислоты с раствором гидроксида кальция, содержащим 37 г Са(ОН)2.
Са(ОН)2+H2SO4= CaSO4 +2H2O

n(Ca(OH)2)=37/74=0,5 моль
По уравнению реакции n(Ca(OH)2)=n(CaSO4) , значит количество вещества сульфата кальция равна 0,5 моль,  то   m(CaSO4)=0,5*134=67г
Ответ:m(CaSO4)=67г

Answer 2

Creating a Neutralization Reaction Problem

To create a problem based on the reaction of neutralization, we can use the following information:

- Mass of Reacting Substance: If the mass of one of the substances involved in the neutralization reaction is known, we can use it to calculate various aspects of the reaction.

Let's create a problem based on this information.

Problem: A student has 25 grams of hydrochloric acid (HCl) and wants to neutralize it with sodium hydroxide (NaOH). If the student knows the mass of the sodium hydroxide used, which is 40 grams, calculate the following: 1. The balanced chemical equation for the neutralization reaction. 2. The amount of water produced in the reaction. 3. The limiting reactant in the reaction. 4. The mass of the excess reactant left after the reaction is complete.

Solving the Neutralization Reaction Problem

Let's solve the problem step by step.

1. Balanced Chemical Equation: The balanced chemical equation for the neutralization reaction between hydrochloric acid and sodium hydroxide is as follows: ``` HCl + NaOH → NaCl + H2O ```

2. Amount of Water Produced: According to the balanced chemical equation, 1 mole of HCl reacts with 1 mole of NaOH to produce 1 mole of water. Using the given masses of HCl and NaOH, we can calculate the amount of water produced.

3. Limiting Reactant: To determine the limiting reactant, we compare the moles of each reactant to the stoichiometry of the balanced chemical equation.

4. Mass of Excess Reactant: After determining the limiting reactant, we can calculate the mass of the excess reactant left after the reaction is complete.

Let's proceed with the calculations based on the given information.