Question

CuSO4 → FeSO4 → Fe(OH) → FeO → Fe (NO3)21)CuSO4+Fe....→ FeSO4+Cu​

Answer 1

Объяснение:

CuSO4+Fe=FeSO4+Cu

FeSO4+2NaOH=Fe(OH)2+Na2SO4

Fe(OH)2->FeO+H2O

FeO+2HNO3=Fe(NO3)2+H2O

Answer 2

The reaction you're describing appears to involve the displacement of copper (Cu) by iron (Fe) from their respective sulfate compounds. This is a type of single displacement reaction. Here's the balanced chemical equation for the reaction:

CuSO4 + Fe → FeSO4 + Cu

In this reaction:

1. Copper sulfate (CuSO4) and iron (Fe) are the reactants.
2. Iron sulfate (FeSO4) and copper (Cu) are the products.
3. The iron displaces the copper in the sulfate compound, resulting in the formation of iron sulfate and the release of copper.

It's important to balance the equation, so the number of atoms of each element is the same on both sides of the reaction:

CuSO4 + Fe → FeSO4 + Cu

This balanced equation shows the reaction between copper sulfate and iron to form iron sulfate and copper.