Question

Если в 1 литре жесткой воды содержится 108 г Ca(HCO3)2 то сколько потребуется сульфата алюминия для смягчения 5 л такой воды

Answer 1

     108г              Хг
3Ca(HCO3)2 +Al2(SO4)3 = 3CaSO4 +2Al(HCO3)3
     606г             342г

1) X= (108x342) : 606;   Х=61г.( для  1 литра воды)
2) 61х5= 305 г.
Ответ: 305 г.

Answer 2

Calculating the Amount of Aluminum Sulfate Needed to Soften Water

To calculate the amount of aluminum sulfate needed to soften 5 liters of water containing 108g of Ca(HCO3)2 per liter, we can use the following formula:

Amount of Aluminum Sulfate (g) = (Molecular Weight of Ca(HCO3)2 / 2) * Volume of Water (L)

Where: - Molecular Weight of Ca(HCO3)2 = 162.114 g/mol - Volume of Water = 5 L

Using the given molecular weight of Ca(HCO3)2 and the volume of water, we can calculate the amount of aluminum sulfate required.

Calculation

Amount of Aluminum Sulfate (g) = (162.114 / 2) * 5

Amount of Aluminum Sulfate (g) = 405.285 g

Therefore, approximately 405.285 grams of aluminum sulfate would be needed to soften 5 liters of water containing 108g of Ca(HCO3)2 per liter.