Question

Вычислить количества вещества и массу кислорода который образовывается при разложении 651г оксида ртути(II) составить пропорцию

Answer 1

    651 г                                                   Х моль, Х г

   2Hg2O        =          4Hg             +        O2

n = 2 моль                                            n = 1 моль

M = 416 г/моль                                    M = 32 г/моль

m = 832 г                                             m = 32 г

651 г Hg2O  -   Х г О2

832 г Hg2O  -   32 г О2

m(O2) = 651 * 32 / 832 = 25 г

651 г Hg2O    -    Х моль О2

832 г Hg2O    -  1 моль О2

n(O2) = 651 *1 / 832 = 0,8 моль

Answer 2

Calculation of the Amount of Substance and Mass of Oxygen Produced

To calculate the amount of substance and mass of oxygen produced during the decomposition of 651 grams of mercury(II) oxide (HgO), we can use the stoichiometry of the reaction. The balanced equation for the decomposition of mercury(II) oxide is:

2HgO → 2Hg + O2

According to the stoichiometry of the reaction, for every 2 moles of mercury(II) oxide decomposed, 1 mole of oxygen is produced. Therefore, we need to convert the mass of mercury(II) oxide to moles and then use the mole ratio to determine the amount of oxygen produced.

First, let's calculate the amount of substance (moles) of mercury(II) oxide using its molar mass. The molar mass of mercury(II) oxide (HgO) is the sum of the atomic masses of mercury (Hg) and oxygen (O):

Molar mass of HgO = (atomic mass of Hg) + (atomic mass of O)

Now, let's calculate the molar mass of HgO using the atomic masses from the periodic table.

Next, we can use the molar mass of HgO to convert the mass of HgO to moles using the following equation:

Amount of substance (moles) = Mass (grams) / Molar mass (grams/mole)

After calculating the amount of substance (moles) of HgO, we can use the mole ratio from the balanced equation to determine the amount of substance (moles) of oxygen produced. Since the mole ratio is 1:1 between HgO and O2, the amount of substance (moles) of oxygen will be the same as the amount of substance (moles) of HgO.

Finally, we can convert the amount of substance (moles) of oxygen to mass using the molar mass of oxygen. The molar mass of oxygen (O2) is the sum of the atomic masses of two oxygen atoms.

Now, let's perform the calculations:

1. Calculate the molar mass of HgO using the atomic masses of Hg and O from the periodic table. 2. Convert the mass of HgO to moles using the molar mass of HgO. 3. Determine the amount of substance (moles) of oxygen produced using the mole ratio from the balanced equation. 4. Convert the amount of substance (moles) of oxygen to mass using the molar mass of oxygen.

Calculation:

1. Molar mass of HgO: - Atomic mass of Hg = - Atomic mass of O = - Molar mass of HgO = (2 * Atomic mass of Hg) + Atomic mass of O

2. Convert the mass of HgO to moles: - Mass of HgO = 651 grams - Amount of substance (moles) of HgO = Mass of HgO / Molar mass of HgO

3. Determine the amount of substance (moles) of oxygen produced: - Amount of substance (moles) of oxygen = Amount of substance (moles) of HgO

4. Convert the amount of substance (moles) of oxygen to mass: - Molar mass of O2 = 2 * Atomic mass of O - Mass of oxygen = Amount of substance (moles) of oxygen * Molar mass of O2

Now, you can perform the calculations using the given values and the information provided above.