Question

Сколько литров O2 ( при н.у) потребуется для превращения 4 г Ca в CaO? Ar(Ca)= 40.

Answer 1

2Ca +O2 = 2CaO

n(Ca) = 2 моль, M= 40 г/ моль, m= 80 г

n(O2) = 1 моль, Vm = 22,4 л/моль, V= 22,4 л

4 г Са    -      V(л) О2

80 г Са  -      22,4 л  О2

V(О2) = 22,4 * 4 / 80 =

Answer 2

Calculating the Amount of O2 Required to Convert 4g of Ca to CaO

To calculate the amount of O2 required to convert 4g of Ca to CaO, we can use stoichiometry to determine the molar ratio between Ca and O2 in the reaction. From the given information, the molar mass of Ca is 40 g/mol.

The balanced chemical equation for the conversion of Ca to CaO is:

Ca + O2 → CaO

From the balanced equation, we can see that 1 mole of Ca reacts with 1 mole of O2 to produce 1 mole of CaO.

To find the amount of O2 required, we can follow these steps:

1. Calculate the moles of Ca using the given mass and molar mass. 2. Use the mole ratio from the balanced chemical equation to find the moles of O2 required. 3. Convert the moles of O2 to liters at standard temperature and pressure (STP).

Calculation Steps:

1. Calculate the moles of Ca: - Given mass of Ca = 4g - Molar mass of Ca (Ar(Ca)) = 40 g/mol - Moles of Ca = Given mass / Molar mass - Moles of Ca = 4g / 40 g/mol - Moles of Ca = 0.1 mol

2. Use the mole ratio to find the moles of O2: - From the balanced chemical equation, the mole ratio of Ca to O2 is 1:1. - Therefore, moles of O2 required = Moles of Ca = 0.1 mol

3. Convert moles of O2 to liters at STP: - 1 mole of any gas at STP occupies 22.4 liters. - Therefore, the volume of O2 required = Moles of O2 * 22.4 L/mol - Volume of O2 required = 0.1 mol * 22.4 L/mol - Volume of O2 required = 2.24 liters

Answer:

The amount of O2 required to convert 4g of Ca to CaO at standard temperature and pressure (STP) is 2.24 liters