Question

CH4->C2H2-C6H6->C6H6NO2->C6H6NH2->C6H6NH3CL​

Answer 1

Ответ:

2CH₄ → C₂H₂ + 3H₂

3C₂H₂ → C₆H₆

2C₆H₆ + 2NO₂ → 2C₆H₅NO₂ + H₂

C₆H₅NO₂ + 3H₂ → C₆H₅NH₂ + 2H₂O

C₆H₅NH₂ + HCl → (C₆H₅NH₃)Cl

Answer 2

The series of chemical reactions you've provided appears to represent the transformation of methane (CH4) into benzylammonium chloride (C6H6NH3Cl) through several intermediate steps. Let's break down each step:

1. CH4 (Methane) -> C2H2 (Acetylene): CH4 can be converted into C2H2 through various processes, such as steam methane reforming or partial oxidation.

2. C2H2 (Acetylene) -> C6H6 (Benzene): This step involves the polymerization of acetylene molecules to form benzene. Acetylene molecules (C2H2) can combine to form the ring structure of benzene (C6H6).

3. C6H6 (Benzene) -> C6H6NO2 (Nitrobenzene): Nitration of benzene can be achieved by reacting benzene with nitric acid (HNO3) and sulfuric acid (H2SO4). This reaction substitutes a nitro group (-NO2) for one of the hydrogen atoms on the benzene ring.

4. C6H6NO2 (Nitrobenzene) -> C6H6NH2 (Aniline): The reduction of nitrobenzene can be carried out using various reducing agents like iron and hydrochloric acid (Fe/HCl) to yield aniline (C6H6NH2).

5. C6H6NH2 (Aniline) -> C6H6NH3Cl (Benzylammonium Chloride): Aniline can be converted into benzylammonium chloride (C6H6NH3Cl) by reacting it with hydrochloric acid (HCl). This reaction forms a salt, where the amino group (-NH2) on aniline is protonated to become -NH3+ and combines with chloride ions from HCl to form the chloride salt.

Each of these steps represents a distinct chemical reaction, and the overall transformation from methane to benzylammonium chloride involves a series of reactions with specific reagents and conditions. It's worth noting that in practice, these reactions may require careful control of reaction conditions, temperature, and catalysts to achieve high yields and selectivity.