Question

2H2O = 2H2 + O - 571,6 кДж

Answer 1

2 моль Н2О - 571,6 кДж
х моль Н2О - 285,6 кДж
х = 2 * 285,6 / 571,6 = 1 моль.

Answer 2

The chemical equation you provided appears to be the decomposition of water (H2O) into hydrogen gas (H2) and oxygen gas (O). The given "-571.6 kJ" represents the enthalpy change (∆H) of the reaction, indicating that the reaction is exothermic, meaning it releases energy in the form of heat.

The balanced chemical equation for the reaction is:

2H2O(l) → 2H2(g) + O2(g)

In this equation, "(l)" represents a liquid state, and "(g)" represents a gaseous state.

The enthalpy change of -571.6 kJ indicates that 571.6 kilojoules of energy are released per mole of water decomposed in the reaction. This value is negative because the reaction releases energy.

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