Question

3c+4hno3=3co2+4no+2h2o полуреакция???

Answer 1

Да вроде не помню точно

Answer 2

The chemical equation you provided represents a balanced equation for the reaction between 3 moles of compound "C" (carbon) and 4 moles of nitric acid (HNO3) to produce 3 moles of carbon dioxide (CO2), 4 moles of nitrogen monoxide (NO), and 2 moles of water (H2O).

To find the corresponding half-reactions, we need to separate the oxidation and reduction processes. The half-reaction for the oxidation (loss of electrons) and reduction (gain of electrons) can be written as follows:

1. Oxidation Half-Reaction: C (carbon) is oxidized from its elemental state (0 oxidation state) to the +4 oxidation state in CO2.

C (elemental) → CO2 C → CO2 (balanced)

2. Reduction Half-Reaction: Nitric acid (HNO3) is reduced, and nitrogen changes its oxidation state from +5 to +2 in nitrogen monoxide (NO).

HNO3 + 2H+ + 2e- → NO + 2H2O (Notice that 2 electrons are added on the left side to balance the charge.)

The overall balanced chemical equation for the reaction is:

3C + 4HNO3 → 3CO2 + 4NO + 2H2O