Question

CH3-CH=CH2+Cl2 (500 C)-? CH3-CH=CH2+KMnO4(H20,O)-? 2-бром-2-бутен+KOH, спирт=? Помогите плиз(

Answer 1

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Answer 2

Certainly, I can help you with these chemical reactions! Let's go through each one step-by-step:

1. CH3-CH=CH2 + Cl2 (500°C) This is a reaction between propene (CH3-CH=CH2) and chlorine gas (Cl2) at 500°C. The reaction is an example of an addition reaction. The double bond in propene will be broken, and chlorine atoms will add to the carbon atoms to form a new compound.

The reaction will yield 1,2-dichloropropane: CH3-CH(Cl)-CH2Cl

2. CH3-CH=CH2 + KMnO4 (H2O, O) This reaction involves the reaction of propene (CH3-CH=CH2) with potassium permanganate (KMnO4) in the presence of water (H2O) and oxygen (O). This reaction is an example of an oxidative cleavage reaction. The double bond in propene will be cleaved, and new functional groups will be formed.

The products of the reaction will depend on the reaction conditions, but one possible outcome is the formation of two carboxylic acids: CH3-COOH + CH3-CHOH-COOH

3. 2-bromo-2-butene + KOH in alcohol (CH3CH2OH) In this reaction, 2-bromo-2-butene will react with potassium hydroxide (KOH) in an alcohol solvent (e.g., ethanol, CH3CH2OH). This is an example of an elimination reaction, specifically a dehydrohalogenation.

The reaction will yield 2-butyne: CH3-C≡C-CH3

Please note that chemical reactions can have multiple possible outcomes based on reaction conditions and other factors. The mentioned products are one possibility for each reaction. If you have specific reaction conditions or any other requirements, let me know, and I can assist you further!