Question

M(Cl2)=300г V (Cl2)-?

Answer 1

V(cl2) = (300×22.4)/71 = 94.64л

Answer 2

To calculate the volume of chlorine gas (Cl2) using the given mass of 300 grams, you'll need to know the molar mass of chlorine gas. Chlorine (Cl2) has a molar mass of approximately 70.906 grams per mole.

The relationship between moles, mass, and molar mass is given by the formula:

moles = mass / molar mass

Let's calculate the number of moles of Cl2 first:

moles of Cl2 = 300 grams / 70.906 g/mol ≈ 4.23 moles

Now, we can use the ideal gas law to find the volume of the gas. The ideal gas law is given by:

PV = nRT

Where: P = pressure of the gas (usually given in atmospheres, atm) V = volume of the gas (unknown, we need to find this) n = number of moles of the gas R = ideal gas constant (approximately 0.0821 L.atm/mol.K) T = temperature of the gas in Kelvin (K)

Since the pressure and temperature of the gas are not provided, we can't find the volume using the ideal gas law with the given information. If you have the values for pressure and temperature, please provide them, and I'll be happy to assist you further in calculating the volume of chlorine gas.