Question

Дано: w(H)-2,6% w(Si)-35,9% w(O)-61,5% Найти:HxSiyOz-?

Answer 1

m (HxSiyOz)=100г

m(H)= 2,6%

m(Si)=35,9%

m(O)=61,5%

x:y:z=m(H)/M(H):m(Si)/M(Si):m(O)/M(O)

x:y:z=2,6/1:35,9/28:61,5/16

x:y:z=2,6:1,28:3,84

x:y:z=0,4:3:0,3

Как решать правельно но вот с цифрами я не уверена

Answer 2

To find the chemical formula for HxSiyOz, we need to determine the subscripts x, y, and z representing the number of atoms of each element present in the compound.

Given the percentages of each element in the compound: w(H) = 2.6% w(Si) = 35.9% w(O) = 61.5%

Let's assume we have 100 grams of the compound. Then, we can calculate the masses of each element in those 100 grams:

Mass of H = 2.6% of 100g = 2.6g Mass of Si = 35.9% of 100g = 35.9g Mass of O = 61.5% of 100g = 61.5g

Next, we need to find the molar masses of each element:

Molar mass of H = 1 g/mol Molar mass of Si = 28.0855 g/mol Molar mass of O = 16 g/mol

Now, let's find the moles of each element:

Moles of H = Mass of H / Molar mass of H = 2.6g / 1 g/mol ≈ 2.6 moles Moles of Si = Mass of Si / Molar mass of Si = 35.9g / 28.0855 g/mol ≈ 1.28 moles Moles of O = Mass of O / Molar mass of O = 61.5g / 16 g/mol ≈ 3.84 moles

To get whole numbers for the subscripts, we can divide all the mole values by the smallest one, which is approximately 1.28:

Moles of H (rounded) = 2.6 moles / 1.28 ≈ 2 Moles of Si (rounded) = 1.28 moles / 1.28 ≈ 1 Moles of O (rounded) = 3.84 moles / 1.28 ≈ 3

Now we have the whole-number ratios of the atoms, giving us the chemical formula:

H2SiO3

So, the chemical formula for the compound is H2SiO3.