Question

Ca+2Hм20 — Ca(OH)2+H2| Масса Ca=40г Найти H2|

Answer 1

Сa + 2 H2O = Ca(OH)2 + H2

по уравнению реакции n(Ca) = n(H2)

n(Ca) = m / M(Ca) = 40 / 40 = 1 моль: n(H2) = 1 моль

m(H2) = n * M(H2) = 1 * 2 = 2 г

Answer 2

To find the mass of H2 produced in the reaction, we first need to determine the stoichiometry of the reaction. The balanced chemical equation for the reaction between Ca and H2O is as follows:

Ca + 2H2O -> Ca(OH)2 + H2

From the equation, we can see that 1 mole of Ca produces 1 mole of H2. To calculate the mass of H2 produced, we can follow these steps:

Step 1: Calculate the number of moles of Ca (given mass of Ca = 40g) Step 2: The number of moles of H2 produced will be the same as the number of moles of Ca. Step 3: Calculate the mass of H2 using the molar mass of hydrogen (H2).

Step 1: Calculate the number of moles of Ca Molar mass of Ca (Ca) = 40.08 g/mol (approximately 40 g/mol) Number of moles of Ca = Mass of Ca / Molar mass of Ca Number of moles of Ca = 40 g / 40.08 g/mol ≈ 0.998 mol

Step 2: The number of moles of H2 produced is the same as the number of moles of Ca, which is approximately 0.998 mol.

Step 3: Calculate the mass of H2 Molar mass of H2 (H2) = 2.016 g/mol (approximately 2 g/mol) Mass of H2 = Number of moles of H2 × Molar mass of H2 Mass of H2 = 0.998 mol × 2 g/mol ≈ 1.996 g

Therefore, the mass of H2 produced in the reaction is approximately 1.996 grams.