Question

M(CaCo3)=20г найти m(CaO)

Answer 1

Ответ:

Объяснение:

  20 г                   Х г

 CaCO3     ->      CaO     +     CO2

n=1 моль               n=1 моль

М = 100 г/моль    М = 56 г/моль

m=100 г                m=56 г

20 г   СаСО3    -   Х г   СаО

100 г  СаСО3   -  56 г  СаО

m(CaO) = 20 * 56 / 100 = 11,2 г

Answer 2

To find the mass of CaO (calcium oxide) produced from 20 g of CaCO3 (calcium carbonate), we need to consider the stoichiometry of the reaction. The balanced chemical equation for the thermal decomposition of calcium carbonate is:

CaCO3 → CaO + CO2

According to the equation, 1 mole of CaCO3 produces 1 mole of CaO. The molar mass of CaCO3 is approximately 100.09 g/mol, and the molar mass of CaO is approximately 56.08 g/mol.

First, we calculate the number of moles of CaCO3 in 20 g:

moles of CaCO3 = mass / molar mass = 20 g / 100.09 g/mol ≈ 0.1999 mol

Since the reaction is 1:1 in terms of moles between CaCO3 and CaO, we can conclude that:

moles of CaO = moles of CaCO3 ≈ 0.1999 mol

Finally, we calculate the mass of CaO:

mass of CaO = moles of CaO × molar mass = 0.1999 mol × 56.08 g/mol ≈ 11.2 g

Therefore, the mass of CaO produced from 20 g of CaCO3 is approximately 11.2 g.