Question

M(Ca)=80гm (Hcl)=146гНайти:m,V(H2)

Answer 1

Ca + 2HCl → CaCl2 + H2

80 / 40 = X / 2

X = 80 × 2 / 40 = 4 г

80 / 40 = Y / 22,4

Y = 80 × 22,4 / 40 = 44,8

Ответ:

m (H2) = 4 г;

V (H2) = 44,8 л.

Answer 2

Ответ:

m(H2) =4г

V(H2) =44.8л

Answer 3

To find the molar mass (M) of calcium (Ca), the mass of hydrochloric acid (HCl), and the mass of hydrogen gas (H2) produced, we need to use stoichiometry.

Let's assume that the reaction between calcium and hydrochloric acid is as follows:

Ca + 2HCl -> CaCl2 + H2

Given: Mass of calcium (m(Ca)) = 80 g Mass of hydrochloric acid (m(HCl)) = 146 g

Step 1: Calculate the number of moles of calcium and hydrochloric acid. We use the formula:

Number of moles (n) = Mass (m) / Molar mass (M)

Molar mass of calcium (Ca) = 40.08 g/mol (you can find this in the periodic table) Number of moles of calcium (n(Ca)) = m(Ca) / M(Ca) = 80 g / 40.08 g/mol ≈ 1.996 mol

Molar mass of hydrochloric acid (HCl) = 36.46 g/mol for HCl (you can find this in the periodic table) Number of moles of hydrochloric acid (n(HCl)) = m(HCl) / M(HCl) = 146 g / 36.46 g/mol ≈ 4.001 mol

Step 2: Determine the limiting reactant. The limiting reactant is the one that is fully consumed in the reaction. It is the reactant that produces the least amount of product. We compare the mole ratios between Ca and HCl. From the balanced equation, we see that 1 mole of Ca reacts with 2 moles of HCl.

The mole ratio of Ca to HCl is 1:2. Therefore, Ca is the limiting reactant since it has fewer moles (1.996 mol) than the 2 moles of HCl.

Step 3: Calculate the moles of hydrogen gas produced. Since 1 mole of Ca produces 1 mole of H2 (according to the balanced equation), we can directly use the number of moles of Ca as the number of moles of H2.

Number of moles of hydrogen gas (n(H2)) = n(Ca) ≈ 1.996 mol

Step 4: Calculate the mass of hydrogen gas produced. We use the formula:

Mass (m) = Number of moles (n) × Molar mass (M)

Molar mass of hydrogen gas (H2) = 2.016 g/mol (you can find this in the periodic table) Mass of hydrogen gas (m(H2)) = n(H2) × M(H2) ≈ 1.996 mol × 2.016 g/mol ≈ 4.025 g

So, the mass of hydrogen gas produced is approximately 4.025 grams.