Question

C3H8 =1.5моль V(O2)=?

Answer 1

Ответ:

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Answer 2

To determine the volume of oxygen (O2) required for the combustion of 1.5 moles of propane (C3H8), we need to use the balanced chemical equation for the combustion reaction. The balanced equation for the combustion of propane is:

C3H8 + 5O2 -> 3CO2 + 4H2O

From the balanced equation, we can see that 1 mole of propane reacts with 5 moles of oxygen to produce 3 moles of carbon dioxide and 4 moles of water.

Since we have 1.5 moles of propane, we can calculate the moles of oxygen required using the mole ratio:

1 mole of propane : 5 moles of oxygen :: 1.5 moles of propane : x moles of oxygen

x = (5 moles of oxygen / 1 mole of propane) * 1.5 moles of propane x = 7.5 moles of oxygen

Therefore, 1.5 moles of propane would require 7.5 moles of oxygen.

To calculate the volume of oxygen, we need to know the conditions under which the calculation is being performed (temperature and pressure). The ideal gas law can be used to relate the moles of a gas to its volume, temperature, and pressure.

Can you please provide the temperature and pressure conditions so that I can calculate the volume of oxygen?