Question

CН4 → C2H2 → C2H4→ C2H5ОН → СН3-СН=О → СН3-СООН

Answer 1

2CH4 = C2H2 + 3H2

C2H2 + H2 = C2H4

C2H4 + H2O = C2H5OH

C2H5OH + CuO = CH3CHO + Cu + H2O

CH3CHO + Br2 + H2O = CH3COOH + 2HBr

Answer 2

The sequence of chemical reactions you provided represents the transformation of methane (CH4) into acetic acid (CH3-COOH). Let's break down the reactions step by step:

1. CH4 (Methane) → C2H2 (Ethyne or Acetylene)
2. C2H2 (Ethyne) → C2H4 (Ethylene)
3. C2H4 (Ethylene) → C2H5OH (Ethanol)
4. C2H5OH (Ethanol) → CH3-CHO (Acetaldehyde)
5. CH3-CHO (Acetaldehyde) → CH3-COOH (Acetic Acid)

I'll explain each reaction briefly:

1. CH4 (Methane) → C2H2 (Ethyne or Acetylene): This reaction involves the removal of hydrogen atoms from methane, leading to the formation of ethyne (also known as acetylene).

2. C2H2 (Ethyne) → C2H4 (Ethylene): In this reaction, ethyne (acetylene) undergoes a reduction reaction where the triple bond between the two carbon atoms is converted into a double bond, forming ethylene.

3. C2H4 (Ethylene) → C2H5OH (Ethanol): This is an addition reaction where ethylene reacts with water (H2O) to form ethanol (C2H5OH).

4. C2H5OH (Ethanol) → CH3-CHO (Acetaldehyde): In this reaction, ethanol is oxidized to form acetaldehyde (CH3-CHO).

5. CH3-CHO (Acetaldehyde) → CH3-COOH (Acetic Acid): Lastly, acetaldehyde undergoes further oxidation to form acetic acid (CH3-COOH), which is also known as vinegar.

So, the sequence of reactions represents the conversion of methane (CH4) to acetic acid (CH3-COOH) through a series of chemical transformations.