Question

Ba(OH)2 = Ba(OH)2+SO2 = Al(OH)3 = Al(OH)3+HCl = Al(OH)3+CO2 =

Answer 1

Объяснение:

Ba(OH)2--->BaO+H2O

Ba(OH)2+SO2--->BaSO3+H2O

2Al(OH)3--->Al2O3+3H2O

Al(OH)3+3HCl---->AlCl3+3H2O

2Al(OH)3+3CO2--->Al2(CO3)3+3H2O

УДАЧИ)))

Answer 2

It seems like you've provided a series of chemical reactions involving different compounds. Let's break down each reaction step by step:

1. Ba(OH)2 (Barium hydroxide) dissociates into Ba^2+ ions and OH^- ions: Ba(OH)2 → Ba^2+ + 2OH^-

2. Ba(OH)2 (Barium hydroxide) reacts with SO2 (Sulfur dioxide) to form barium sulfite and water: Ba(OH)2 + SO2 → BaSO3 + H2O

3. Al(OH)3 (Aluminum hydroxide) is a compound that doesn't dissociate in the given context.

4. Al(OH)3 (Aluminum hydroxide) reacts with HCl (Hydrochloric acid) to form aluminum chloride and water: Al(OH)3 + 3HCl → AlCl3 + 3H2O

5. Al(OH)3 (Aluminum hydroxide) reacts with CO2 (Carbon dioxide) to form aluminum carbonate and water: 2Al(OH)3 + 3CO2 → Al2(CO3)3 + 6H2O

Please note that these reactions are simplified and may not accurately represent the real-world conditions or stoichiometry. Additionally, the product for the first reaction is not completely balanced, as barium sulfite is usually written as BaSO3 with a charge of +2 for barium and -2 for sulfite. If you need more detailed or specific information about these reactions, please provide additional context or details.