 
M(NaOH)=2гр.,m(HCI)=?
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            It seems like you're trying to perform a chemical reaction between sodium hydroxide (NaOH) and hydrochloric acid (HCl). In order to determine the mass of hydrochloric acid required to react with 2 grams of sodium hydroxide, you need to know the balanced chemical equation for the reaction.
The balanced chemical equation for the reaction between NaOH and HCl is:
NaOH + HCl -> NaCl + H2O
From the equation, you can see that 1 mole of NaOH reacts with 1 mole of HCl to produce 1 mole of NaCl and 1 mole of water (H2O).
The molar mass of NaOH is approximately 40.00 g/mol (22.99 g/mol for Na + 16.00 g/mol for O + 1.01 g/mol for H), and the molar mass of HCl is approximately 36.46 g/mol (1.01 g/mol for H + 35.45 g/mol for Cl).
Since the balanced equation indicates a 1:1 mole ratio between NaOH and HCl, the molar mass of NaOH (40.00 g/mol) is equal to the molar mass of HCl (36.46 g/mol).
Given that you have 2 grams of NaOH, you would need an equal molar amount of HCl to react completely:
m(HCl) = m(NaOH) = 2 grams
So, you would need 2 grams of hydrochloric acid to react with 2 grams of sodium hydroxide completely based on the balanced equation.
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