
8x + y = -6,-2x + 5y =12


Ответы на вопрос

Ответ:
8x+y=-6 (1)
-2x+5y=12 (2) *4 -8x+20y=48 +(1)
→21y=48-6 21y=42 y=2
8x+2=6 8x=4 x=0.5
Объяснение:



To solve the system of equations:
8x + y = -6 ---(1) -2x + 5y = 12 ---(2)
There are multiple methods to solve this system of equations, such as substitution, elimination, or matrix methods. Let's use the elimination method.
To eliminate the variable "x" in the system, we can multiply equation (1) by 2 and equation (2) by 8, which will make the coefficients of "x" in both equations cancel each other out when added together.
Multiplying equation (1) by 2:
2(8x + y) = 2(-6) 16x + 2y = -12 ---(3)
Multiplying equation (2) by 8:
8(-2x + 5y) = 8(12) -16x + 40y = 96 ---(4)
Now, let's add equations (3) and (4) together:
(16x + 2y) + (-16x + 40y) = -12 + 96 16x - 16x + 2y + 40y = 84 42y = 84
Divide both sides of the equation by 42:
42y/42 = 84/42 y = 2
Now that we have the value of "y," we can substitute it back into equation (1) to find the value of "x":
8x + y = -6 8x + 2 = -6 8x = -6 - 2 8x = -8 x = -8/8 x = -1
Therefore, the solution to the system of equations is x = -1 and y = 2.


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